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3 years ago

In Which figure below is the trend line drawn correctly

Physics

1 answer:

saul85 [17]3 years ago

5 0

Answer:

<em>The first graph is the trend line. </em>

Explanation:

<u>Trend Line </u>

It's a line indicating the tendency of something being measured or evaluated. The trend line is meant to represent an approximation of a set of points of a measured magnitude.

We have three possible 'trend lines' to choose from. The second is not a line, so it's not the correct option. The third is not a line either, it's just a graph who joins all the measured points. It doesn't mark a trend.

The first graph is a trend line because it's a single line and can be used to represent the whole set of values .

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an object is held 33.5 cm from a convex mirror. it creates a virtual image of magnification 0.253. what is the focal length of t

MaRussiya [10]

Answer:

Magnification= -image distance/object distance

.253=image distance/33.5

image distance= 8.48 cm

7 0

2 years ago

describe the relationship between the direction of the velocity vector and the direction of the acceleration for a body moving i

Xelga [282]

Answer:

a = v²/r

Explanation:

The acceleration of a body moving in a circular path is known as the centripetal acceleration. This is the acceleration of a body that keeps the body within the circular path. It is written in terms of the linear velocity v and the radius of the circle of rotation as shown;

a = v²/r where

v is the linear velocity

r is the radius

a is the centripetal acceleration

7 0

3 years ago

Please helppppp asapppp

yuradex [85]

The picture won’t load

5 0

3 years ago

. If a pendulum-driven clock gains 5.00 s/day, what fractional change in pendulum length must be made for it to keep perfect tim

inn [45]

Answer:

The appropriate response will be "Length must be increased by 0.012%".

Explanation:

The given values is:

ΔT = 5 s/day

Now,

⇒ $\frac{\Delta T}{T} =\frac{5}{24\times 60\times 60}$

On multiplying both sides by "100", we get

⇒ $\frac{\Delta T}{T}\times 100 =\frac{500}{24\times 60\times 60}$

⇒ $\frac{\Delta T}{T}\times 100=0.005787$ (%)

∵ $T=2\pi\sqrt{\frac{l}{g} }$

On substituting the values, we get

⇒ $\frac{\Delta T}{T}$ % = $\frac{1}{2}\times \frac{\Delta l}{l}$ %

On applying cross multiplication, we get

⇒ $\frac{\Delta l}{l}$ % = $2\times \frac{\Delta T}{T}$ %

⇒ = $2\times 0.05787$

⇒ = $0.011574$

⇒ = $0.012$ %

6 0

3 years ago

The diagram shows the flow of water through a hydroelectric power station. The falling water

KonstantinChe [14]

Answer:

KE = $\frac{1}{2}$ m $v^{2}$

Explanation:

In the generation of energy from hydroelectric power station, the motion of water, and the turbines are paramount. The falling flowing water turns the blades of the turbine, which in-turn causes the movement of a coil within a strong magnetic field.

The motion of the coil which cuts the strong magnetic field induces current. Thus, the system generates electrical energy.

The equation that links kinetic energy (KE), mass (m) and speed (v) can be expressed as:

KE = $\frac{1}{2}$ m $v^{2}$

7 0

3 years ago