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Anvisha [2.4K]
4 years ago
12

A student measures the mass of an 8 cm3 block of brown sugar to be 12.9 g. What is the density of the brown sugar?

Chemistry
1 answer:
Luba_88 [7]4 years ago
4 0

Answer:

The answer is

<h2>1.61 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}

From the question

mass = 12.9 g

volume = 8 cm³

The density of the block is

density =  \frac{12.9}{8}  \\  = 1.6125

We have the final answer as

<h3>1.61 g/cm³</h3>

Hope this helps you

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Describe the many different forms of energy involved with stretching and releasing a rubber band. What other processes are simil
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Conversion of kinetic energy to potential energy (chemo mechanical energy)

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Conversion of the stored potential energy in the stretched to kinetic energy

By remaining in a stretched condition, the rubber is in a state of high potential energy, when the force holding the rubber in place is removed, due to the laws of thermodynamics, the polymers in the rubber curls back to their state of "random" tangled mass releasing the stored potential energy in the process and doing work such as moving items placed in the rubber's path of motion such as an object that has weight, w then takes up the kinetic energy 1/2×m×v² which can can result in the flight of the object.

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Compose one to two typewritten paragraphs summarizing the content of your poster. a) Explain in detail what happens as thermal e
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If 211 mL of water is added to 5.00 mL of 3.24 M NaCl solution,
Softa [21]

Answer:

0.075M

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-The concentration of a solution is defined as the mass of the solute divided by the volume of the solution:

Concentration=\frac{Mass \ Solute}{Volume \ of \ Solution}

-We the solve the molarity problem as follows:

M_1V_1=M_2V_2\\\\V_2=V_1+211=211+5=216mL\\\\\therefore M_2=\frac{M_1V_1}{V_2}\\\\=\frac{3.24\times 5}{216}\\\\\\=0.075\ M

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6 0
4 years ago
Energy in the amount of 420 J is added to a 35 g sample of water at a temperature of 10°C. What is the final temperature of the
Vsevolod [243]

The <em>final temperature </em><em>of the</em><em> water, T2</em> = <em>38.57°C</em>

Temperature can be defined as a measure of the degree of hotness or coldness of a physical object (body). Thus, it is measured with a thermometer and its units are degree Celsius (°C), Fahrenheit (°F) and Kelvin (°K).

A calorie refers to the amount of heat required to raise the temperature of a gram of water by one (1) degree Celsius (1°C).

<u />

<u>Given the following data:</u>

  • Quantity of energy = 420J
  • Mass = 35 grams
  • Initial temperature, T1 = 10°C

The specific heat capacity of water is 4.2 J/g°C.

To find the final temperature of the water (T2):

Mathematically, the quantity of energy (heat capacity) is given by the formula;

Q = mcdt

Where;

  • Q represents the heat capacity or quantity of heat.
  • M represents the mass of an object.
  • C represents the specific heat capacity of water.
  • dt represents the change in temperature.

Substituting the values into the formula, we have;

420 = 3.5 \; * \; 4.2 \; * \;  dt

420 = 14.7 \; * \; dt\\\\dt = \frac{420}{14.7}

Change in temperature, dt = 28.57°C

Next, we would solve for the final temperature by using this formula;

dt = T2 - T1

28.57 = T_{2} - 10\\\\T_{2} = 28.57 \; + \; 10\\\\T_{2} = 38.57

<em>Final temperature, T2 = 38.57°C</em>

<em>Therefore</em><em>, </em><em>the</em><em> final temperature </em><em>of the</em><em> water, T2</em> is equal to <em>38.57°C</em>

For more information visit: brainly.com/question/22736508

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