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3 years ago

10

Calculate the mass in grams of iodine (i 2 ) that will react completely with 20.4 g of aluminum (al) to form aluminum iodide (al

i

1 answer:

garik1379 [7]3 years ago

8 0

3I₂ + 2Al → 2AlI₃

m(I₂)=3M(I₂)m(Al)/{2M(Al)}

m(I₂)=3*253.8*20.4/{2*27.0}=287.64 g

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From Young's experiment, how does the frequency of light affect the number of lines observed?

Marina CMI [18]

Answer : (C) "Higher frequencies have larger spaces between lines".

Explanation:

In Young's experiment, the condition for constructive interference is given by :

$dsin\theta=n\lambda$ .........(1)

n is order or number of lines observed

d is distance between slits

$\theta$ is the angle between the path and the line from screen to the slits.

We also know that, $c=\nu \lambda$

or

$\lambda=\dfrac{c}{\nu}$

where,

c is the speed of light

$\nu$ is frequency

$\lambda$ is wavelength

So, equation (1) turns into

$dsin\theta=n\dfrac{c}{\nu}$

$\nu=\dfrac{n\ c}{d\ sin\theta}$

So,

$\nu\propto n$

or

Higher frequencies have larger spaces between line.

So, correct option is (C).

3 0

2 years ago

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Consider the following reaction between mercury(II) chloride and oxalate ion.

Alina [70]

<u>Answer:</u> The rate law of the reaction is $\text{Rate}=k[HgCl_2][C_2O_4^{2-}]^2$

<u>Explanation:</u>

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$2 HgCl_2(aq.)+C_2O_4^{2-}(aq.)\rightarrow 2Cl^-(aq.)+2CO_2(g)+Hg_2Cl_2(s)$

Rate law expression for the reaction:

$\text{Rate}=k[HgCl_2]^a[C_2O_4^{2-}]^b$

where,

a = order with respect to $HgCl_2$

b = order with respect to $C_2O_4^{2-}$

Expression for rate law for first observation:

$3.2\times 10^{-5}=k(0.164)^a(0.15)^b$ ....(1)

Expression for rate law for second observation:

$2.9\times 10^{-4}=k(0.164)^a(0.45)^b$ ....(2)

Expression for rate law for third observation:

$1.4\times 10^{-4}=k(0.082)^a(0.45)^b$ ....(3)

Expression for rate law for fourth observation:

$4.8\times 10^{-5}=k(0.246)^a(0.15)^b$ ....(4)

Dividing 2 from 1, we get:

$\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{(0.164)^a(0.45)^b}{(0.164)^a(0.15)^b}\\\\9=3^b\\b=2$

Dividing 2 from 3, we get:

$\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{(0.164)^a(0.45)^b}{(0.082)^a(0.45)^b}\\\\2=2^a\\a=1$

Thus, the rate law becomes:

$\text{Rate}=k[HgCl_2]^1[C_2O_4^{2-}]^2$

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2 years ago

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otez555 [7]

Answer:

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In nuclear physics, the sum of the numbers of protons and neutrons present in the nucleus of an atom.

Please vote brainliest!

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1 year ago

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leonid [27]

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3 years ago

How many grams are in 4.5 moles of NaF?

Ilia_Sergeevich [38]

Answer:

3139542g

Explanation:

That's because if you talk about

4.5

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