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Free_Kalibri [48]
3 years ago
5

Balance the following redox equations by the ion-electron method:? A) H2O2 + Fe 2+ ---> Fe 3+ + H2O (in the acidic solution)

C) CN- + MnO4- ---> CNO- +MnO2 (in basic solution) E) S2O2/3- + I2 ---> I- + S4O2/6- (in acidic solution)
Chemistry
1 answer:
Vaselesa [24]3 years ago
3 0
We balance the given reactions above by following the rules in balancing redox reactions in acidic or basic solutions. Balance the atoms aside from the O and H atoms. Then we balance the Os and Hs by adding H2O or H+. Finally, we balance the total charge of the reactant and product by adding e-. We do as follows:

<span>A) H2O2 + Fe 2+ ---> Fe 3+ + H2O (in the acidic solution)
</span><span>   2H+ + </span>H2O2 + Fe 2+ ---> Fe 3+ + 2H2O 
   e- + 2H+ + H2O2 + Fe 2+ ---> Fe 3+ + 2H2O 
<span>
C) CN- + MnO4- ---> CNO- +MnO2 (in basic solution)
</span>     CN- + MnO4- ---> CNO- +MnO2 + H2O
     2H+ + CN- + MnO4- ---> CNO- +MnO2 + H2O
     2OH- + 2H+ + CN- + MnO4- ---> CNO- +MnO2 + H2O + 2OH-
     2H2O + CN- + MnO4- ---> CNO- +MnO2 + H2O + 2OH-
     e- + H2O + CN- + MnO4- ---> CNO- +MnO2 + 2OH-
<span>
E) S2O2/3- + I2 ---> I- + S4O2/6- (in acidic solution)
    2</span>S2O2/3- + I2 ---> 2I- + S4O2/6- 
    4H+ + 2S2O2/3- + I2 ---> 2I- + S4O2/6- + 2H2O
    6e- + 4H+ + 2S2O2/3- + I2 ---> 2I- + S4O2/6- + 2H2O

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3 years ago
Assume that all of this fossil fuel is in the form of octane (C8H18) and calculate how much CO2 in kilograms is produced by worl
AnnZ [28]

The given question is incomplete. the complete question is:

The world burns the fossil fuel equivalent of approximately 9.50\times 10^{12} kg of petroleum per year. Assume that all of this petroleum is in the form of octane. Calculate how much CO2 in kilograms is produced by world fossil fuel combustion per year.( Hint: Begin by writing a balanced equation for the combustion of octane.)

Answer: 29\times 10^{12}kg

Explanation:

Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

2_C8H_{18}+17O_2\rightarrow 16CO_2+18H_2O

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of octane}=\frac{9.50\times 10^{12}\times 10^3g}{114g/mol}=0.083\times 10^{15}moles

According to stoichiometry :

As 2 moles of octane give = 16 moles of CO_2

Thus 0.083\times 10^{15}moles of octane give =\frac{16}{2}\times 0.083\times 10^{15}=0.664\times 10^{15}moles  of CO_2

Mass of CO_2=moles\times {\text {Molar mass}}=0.664\times 10^{15}moles\times 44g/mol=29.2\times 10^{15}g=29.2\times 10^{12}kg

Thus 29\times 10^{12}kg of CO_2 is produced by world fossil fuel combustion per year.

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3 years ago
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Alexxandr [17]

Answer:

Explanation:

It is a colorless liquid. It reacts with water to give adipic acid. It is prepared by treatment of adipic acid with thionyl chloride.

Adipoyl Chloride can be used in the synthesis of nylon. Also it is used in the synthesis of chiral polymer for membrane application.

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3 years ago
Can alpha radiation affect electronics
Tom [10]

Answer:

Radiation effects on electrical equipment depend on the equipment and on the type of ionizing radiation to which it is exposed.

 

First, beta radiation has little, if any, effect on electrical equipment because this type of ionizing radiation is easily shielded. The equipment housing and the construction of the parts within the housing will protect the equipment from beta-radiation (high-energy electrons) exposure.

 

Gamma radiation is penetrating and can affect most electrical equipment. Simple equipment (like motors, switches, incandescent lights, wiring, and solenoids) is very radiation resistant and may never show any radiation effects, even after a very large radiation exposure. Diodes and computer chips (electronics) are much more sensitive to gamma radiation. To give you a comparison of effects, it takes a radiation dose of about 5 Sv to cause death to most people. Diodes and computer chips will show very little functional detriment up to about 50 to 100 Sv. Also, some electronics can be "hardened" (made to be not affected as much by larger gamma radiation doses) by providing shielding or by selecting radiation-resistant materials.

 

Some electronics do exhibit a recovery after being exposed to gamma radiation, after the radiation is stopped. But the recovery is hardly ever back to 100% functionality. Also, if the electronics are exposed to gamma radiation while unpowered, the gamma radiation effects are less.

 

Ionizing radiation breaks down the materials within the electrical equipment. For example, when wiring is exposed to gamma rays, no change is noticed until the wiring is flexed or bent. The wire's insulation becomes brittle and will break and may cause shorts in the equipment. The effect on diodes and computer chips is a bit more complex. The gamma rays disrupt the crystalline nature of the inside of the electronic component. Its function is degraded and then fails as more gamma radiation exposure is received by the electronic component.

 

Gamma rays do not affect the signals within the device or the signals received by the device. Nonionizing radiation (like radio signals, microwaves, and electromagnetic pulses) DO mess with the signals within and received by the device. I put a cheap electronic game in my microwave oven at home. It arced and sparked and was totally ruined. I didn’t waste any more of my time playing that game.

Hope this helps.

Explanation:

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As long as the chemical is not used up in the reaction the answer is true
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