Pretty sure the answer is c but not completely positive !
I think they are called Faults.
your answer is 0.00833M the volume was converted into liters
NaOH(aq)+HCl(aq)→NaCl(aq)+H2O(l)
Using the molarity equation, we can find the number of moles of HCl that reacted:
molarity=mol soluteL soln
mol solute=(molarity)(L soln)
mol HCl=(0.105molL)(0.0250L)=0.00263 mol HCl
(volume converted to liters)
Now, using the coefficients of the chemical reaction, we can determine the number of moles of NaOH that reacted:
0.00263mol HCl(1lmol NaOH1mol HCl)=0.00263 mol NaOH
Lastly, we'll use the molarity equation (using given volume of NaOH soln) again to determine the molarity of the sodium hydroxide solution:
molarity=mol soluteL soln
Answer:
Gold: 1.1 x 10²² atoms/cm³
Silver: 4.8 x 10²² atoms/cm³
Explanation:
100 g of the alloy will have 29 g of Au and 71 g of Ag.
19.32 g Au ____ 1 cm³
29 g Au ______ x
x = 1.5 cm³
10.49 g Ag ____ 1 cm³
71 g Ag _______ y
y = 6.8 cm³
The total volume of 100g of the alloy is x+y = 8.3 cm³.
Gold:
196.97 g Au____ 6.022 x 10²³ atoms Au
29 g Au _______ w
w = 8.9 x 10²² atoms Au
8.9 x 10²² atoms Au ____ 8.3 cm³
A ____ 1 cm³
A = 1.1 x 10²² atoms Au
Silver:
107.87 g Ag____ 6.022 x 10²³ atoms Ag
71 g Ag _______ w
w = 4.0 x 10²³ atoms Ag
4.0 x 10²³ atoms Ag ____ 8.3 cm³
B ____ 1 cm³
B = 4.8 x 10²² atoms Ag
