Explanation:
The given reaction equation is as follows.
So, rate constants for different reactants and products written as follows.
As per the reaction equation, the stoichiometric coefficients of reactants and products are as follows.
A = -2
B = -1
C = 1
Therefore,
Hence, 
= 
= 12.5 
Thus, we can conclude that 
and 
are 12.5 .
Faster than the hurricane at least 250 feet
<span>284 g
First, lookup the atomic weights of all the elements involved.
Atomic weight of Calcium = 40.078
Atomic weight of Chlorine = 35.453
Now calculate the molar mass of CaCl2
40.078 + 2 * 35.453 = 110.984
Using that molar mass, calculate how many moles of CaCl2 you have.
445 g / 110.984 g/mol = 4.009586967 mol
Since each molecule of CaCl2 has 2 chlorine atoms, multiply the number of moles of CaCl2 by 2 to get the number of moles of Chlorine atoms.
4.009586967 * 2 = 8.019173935
And finally, multiply by the atomic weight of chlorine.
8.019173935 * 35.453 = 284.3037735
Since you have have 3 significant figures in your data, round the result to 3 significant figures, giving 284 grams.</span>
The answer is C. No all cells have cell walls. Prokaryotes don’t have a nucleus or chloroplast. Leaving C to be correct
Answer:
a) 0.13 g = 0.13X0.001 kg = 1.3 X 10⁻⁴ kg
b) 232 Gg = 232 X 1000000 kg = 2.32 X 10⁸ kg
c) 5.23 pm = 5.23 X 10⁻¹² m
d) 86.3 mg = 86.3 X 10⁻⁶Kg = 8.63 X 10⁻⁵Kg
e) 37.6 cm = 37.6 X 10⁻² m = 3.76 X 10⁻¹m
f) 54 = 5.4 X 10¹
g) 1 Ts = 10¹² seconds
h ) 27 ps = 27 X 10⁻¹² s= 2.7 X 10⁻¹¹ s
i) 0.15 mK = 1.5 X10⁻⁴ K
Explanation:
A scientific notation is a representation of any number which is very large or very small. It is simplification of writing a number.
The SI units of
i) weight = Kg
ii) length = meter
iii) time = second
iv) temperature = K
a) 0.13 g = 0.13X0.001 kg = 1.3 X 10⁻⁴ kg
b) 232Gg
1 Gg = 1000000 kg
232 Gg = 232 X 1000000 kg = 2.32 X 10⁸ kg
c) 5.23 pm
1 pm = 10⁻¹² m
5.23 pm = 5.23 X 10⁻¹² m
d) 86.3 mg
1mg = 10⁻⁶Kg
86.3 mg = 86.3 X 10⁻⁶Kg = 8.63 X 10⁻⁵Kg
e) 37.6cm
1 cm = 10⁻² m
37.6 cm = 37.6 X 10⁻² m = 3.76 X 10⁻¹m
f) 54 (no units)
54 = 5.4 X 10¹
g) 1 Ts = 10¹² seconds
h ) 27 ps
1 ps = 10⁻¹² s
27 ps = 27 X 10⁻¹² s= 2.7 X 10⁻¹¹ s
i) 0.15 mK
1mK = 10⁻³ K
0.15 mK = 1.5 X10⁻⁴ K
