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3 years ago

Which of the following is the major product in the electrophilic addition of HCl to (3S)-2,3-dimethylpent-1-ene?

Chemistry

1 answer:

kvv77 [185]3 years ago

5 0

Answer:

(3S)-2-chloro-2,3-dimethylpentane is produced exclusively.

Explanation:

Electrophilic addition to (3S)-2,3-dimethylpent-1-ene proceeds through a carbocationic intermediate.

In the first step, $H^{+}$ adds onto double bond to produce more stable tertiary carbocation. (protonation)

In the second step, $Cl^{-}$ adds onto carbocation to produce (3S)-2-chloro-2,3-dimethylpentane exclusively.(nucleophilic addition)

So, option (d) is correct.

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Using henry's law, calculate the molar concentration of o2 in the surface water of a mountain lake saturated with air at 20 ∘c a

s2008m [1.1K]

Answer: The molar concentration of oxygen gas in water is $1.43\times 10^{-7} mol/L$ .

Explanation:

Partial pressure of the $O_2$ gas = 685 torr = 0.8905 bar

1 torr = 0.0013 bar

According Henry's law:

$p_{o_2}=K_H\times\chi_{O_2}$

Value of Henry's constant of oxygen gas at 20 °C in water = 34860 bar

$0.0013=34860 bar\times \chi_{O_2}$

$\chi_{O_2}=\frac{0.8905 bar}{34680 bar}=2.56\times 10^{-5}$

Let the number of moles of $O_2$ gas in 1 liter water be n.

1 Liter water = 1000 g of water

Moles of water in 1 L $n_w=\frac{1000 g}{18 g/mol}=55.55 mol$

$\chi_{O_2}=\frac{n}{n+n_w}$

$2.56\times 10^{-5}=\frac{n}{n+55.55}$

$n=1.43\times 10^{-7} moles$

$Molarity=\frac{\text{Moles of}O_2}{Volume}$

Molar concentration of oxygen gas in 1 L of water:

$=\frac{1.43\times 10^{-7} moles}{1 L}=1.43\times 10^{-7} mol/L$

The molar concentration of oxygen gas in water is $1.43\times 10^{-7} mol/L$ .

4 0

3 years ago

Rewrite each equation below with the delta h value included with either the reactants or he products , and identify the reaction

grin007 [14]

I will take a stab at it, but there are not equations, did you forget them?

5 0

3 years ago

Determina el pH de una solución si la concentración de H es 3.5 x 10 molar, e indicar si es acido o bas

erastovalidia [21]

Answer:

Explanation:

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3 years ago

A 5.00-g sample of copper metal at 25.0 °C is heated by the addition of 133 J of energy. The final temperature of the copper is

vekshin1

<u>Answer:</u> The final temperature of the copper is 95°C.

<u>Explanation:</u>

To calculate the final temperature for the given amount of heat absorbed, we use the equation:

$Q= m\times c\times \Delta T$

Q = heat absorbed = +133 J (heat is added to the system)

m = mass of copper = 5.00 g

c = specific heat capacity of copper = 0.38 J/g ° C

$\Delta T={\text{Change in temperature}}=T_2-T_1$

$T_1=25^oC$

Putting values in above equation, we get:

$+133J=5.00g\times 0.38J/g^oC\times (T_2-25)\\\\T_2=95^oC$

Hence, the final temperature of the copper is 95°C.

3 0

3 years ago

Which physical property of the water changes when it reaches its melting point

KiRa [710]

It's temperature changes!

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3 years ago

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