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bekas [8.4K]
4 years ago
10

QUESTION 2

Physics
2 answers:
Mariana [72]4 years ago
8 0
Question 2: Protons
Question 3: Electrons
Question 4: Protons
Question 5: Im pretty sure its electrons
Serggg [28]4 years ago
4 0

2 is protons

3 is electron

4 is protons

5 is neutron

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> Which wave has the smallest amplitude?
stepladder [879]

Answer: Option (1) is the correct answer.

Explanation:

The vertical distance between crest or trough from the origin or equilibrium point is known as amplitude of a wave.

In the given pictures, a wave that shows maximum height from the origin will have the maximum amplitude. Whereas the wave that shows minimum height from the origin will have the smallest amplitude.

Thus, we can conclude that waves shown in option 1 will have the smallest amplitude.

7 0
4 years ago
A loop of area 0.0633 m^2 is oriented perpendicular (0 deg) to a magnetic field. The magnetic field changes in strength from 0.8
frez [133]

Answer:

The magnetic flux change is 0.0877 Wb.

Explanation:

Given that,

Area = 0.0633 m²

Angle = 0°

Magnetic field changes

B_{1}=0.894\ T

B_{2}=2.28\ T

We need to calculate the magnetic flux change

Using formula of flux

\Delta \phi=BA\cos\theta

\Delta \phi=A(B_{f}-B_{i})\cos\theta

Where, B = magnetic field

A = area

Put the value into the formula

\Delta \phi =0.0633\times(2.28-0.894)

\Delta \phi=0.0877\ Wb

Hence, The magnetic flux change is 0.0877 Wb.

8 0
3 years ago
Question 20 of 20
Sphinxa [80]

Answer:

a

Explanation:

hI I

6 0
2 years ago
Pube Goldberg machine is a complicated contraption designed to do a very simple task, like the one shown above
Elanso [62]

Answer:

I think is 2

Explanation:

6 0
3 years ago
a stone is thrown by a person from the top of the building, which is 200m tall. at the same time, another stone is thrown with v
solniwko [45]

Answer:

The time after which the two stones meet is tₓ = 4 s

Explanation:

Given data,

The height of the building, h = 200 m

The velocity of the stone thrown from foot of the building, U = 50 m/s

Using the II equation of motion

                             S = ut + ½ gt²

Let tₓ be the time where the two stones  meet and x be the distance covered from the top of the building

The equation for the stone dropped from top of the building becomes

                            x = 0 + ½ gtₓ²

The equation for the stone thrown from the base becomes

                S - x = U tₓ - ½ gtₓ²  (∵ the motion of the stone is in opposite direction)

Adding these two equations,

                      x + (S - x) = U tₓ

                               S = U tₓ

                               200 = 50 tₓ

∴                                  tₓ = 4 s

Hence, the time after which the two stones meet is tₓ = 4 s   

6 0
3 years ago
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