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3 years ago

A 8kg cat us running 4 m/s. How much kenetic energy is that

1 answer:

3 0

Using the Definition of Kinetic Energy, we have:

$E_{c}= \frac{mv^2}{2} \\ E_{c}= \frac{8*4^2}{2} \\ \boxed {E_{c}=64J}$

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Which of these is emitted during beta decay ?

satela [25.4K]

Answer:

C. a small charged particle.

Explanation:

typically beta radiation emits an electron which is a small negativity charged particle.

hope it helps. :)

4 0

3 years ago

Read 2 more answers

What would be the current of the same wire if it was moved up towards the magnet instead of through the magnetic field?

Aleks04 [339]

Answer:

0 v

Explanation:

3 0

2 years ago

Just this last one!!

Pepsi [2]

Answer:

$47 \ \frac{m}{s}$

Explanation:

s = displacement (m)

u = initial velocity $(\frac{m}{s})$

v = final velocity $(\frac{m}{s})$

a = acceleration $(\frac{m}{s^{2} })$

t = time (s)

s = 235

a = -4.7

v = 0

v² = u² + 2as

(0)² = u² + 2(-4.7)(235)

u² - 2209 = 0

u² = 2209

u = 47

4 0

2 years ago

Read 2 more answers

You can use light produced by _____ to heat food?

Ivan

Electricity/or any source that give a connection of electricity

4 0

3 years ago

Read 2 more answers

A mass of 100 g stretches a spring 5 cm. If the mass is set in motion from its equilibrium position with a downward velocity of

garri49 [273]

Answer:

$w_{0}=14$

$t=\frac{\pi }{14}$

Explanation:

Data

mass m= 100g

Length L= 5cm

we can use:

gm-kL= 0

divide both side by m

g - $\frac{kL}{m}$ =0

where

$\frac{k}{m}$ = $\frac{g}{L}$

$\frac{k}{m}=w_{0}$ ^{2}

so now

$w_{0}^{2}$ = $\frac{9.8*100}{5}$

$w_{0}^{2}=\frac{980}{5}$

$w_{0}^{2}=196$

square both side

$w_{0}=\sqrt{196}$

$w_{0}=14$

We can apply:

u(t)=Acoswt +Bsinwt

u(t)=Acos14t +Bsin14t

u(0)=0 where A=0

therefore

u(0) = Bsin14t

$u^{'}$ (0) = 10 ⇒ 10=14B ⇒ B= $\frac{14}{10}$ B= $\frac{5}{7}$

so now u(t)= $\frac{5}{7}$ sin14t

so t will be:

t= $\frac{\pi }{14}$

t= $\frac{3.14}{14}$

t=0.22 seconds

8 0

3 years ago