Question

Abutcher thrown a cut of beef on spring scales which oscillates about the equilibrium position with a period of T = 0.500 second . The amplitude of the vibration is A= 2.00 centimetre and path length =4.00 Centimetre Find a frequency and maximum acceleration and maximum velocity
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Answer 1

Answer:

f = 1 / T = 1 / .5 = 2 / sec

w (omega) = 2 pi f = 6.28 * 2 = 12.56 / sec

V(max) = w * A = 12.56 / sec * 2 cm = 25.1 cm/sec

A(max) = -w^2 * A = (12.56 /sec)^2 * 2 cm = 316 cm / sec^2

(min was -316 cm/sec^2)