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mylen [45]
3 years ago
12

In a reaction 4 NH3 + 5 O2 → 4 NO + 6 H2O, 1 mole of ammonia reacts with 2 moles of oxygen. Which of these is correct after the

reaction is complete?
A) All the oxygen is consumed.
B) All the ammonia is consumed.
C) 1 mole of oxygen remains.
D) 1 mole of water is produced.
Chemistry
1 answer:
Vsevolod [243]3 years ago
6 0

Answer:

  • <em><u>Option B) All the ammonia is consumed</u></em>

Explanation:

<u>1. Balanced chemical equation (given):</u>

   4NH_3+5O_2\rightarrow 4NO+6H_2O

<u>2. Theoretical mole ratios:</u>

    4molNH_3:5molO_2:4molNO:6H_2O

<u>3. Limiting reactant:</u>

When  1 mole of ammonia is combined with 2 moles of oxygen, the mole ratio is:

                 1molNH_3:2molO_2

Hence, one of the reactants will be completely consumed (the limiting reactant) and, after completion, an excess of the other will remain unreacted.

You need to compare the the actual ratio with the theoretical ratio.

  • 4/5 > 1/2

Hence, NH₃ is in less proportion with respect to oxygen than what is theoretically needed, and the former is the limiting reactant.

Therefore, the 1 mole (all) of ammonia will be consumed, while some oxygen will remain as excess.  This is described by the option B) All the ammonia is consumed.

<u />

<u>4. Analyze the other options:</u>

The amount of oxygen that will react is:

    1molNH_3\times5molO_2/4molNH3=5/4molO_2

And the amount that will remain is:

     2molO_2-4/5molO_2=6/5molO_2

Neither option A) nor C) describe that situation.

The amount of water produced is:

    1molNH_3\times 6molH_2O/4molNH_3=1.5molH_2O, which is not described by the option D).

Hence, the correct answer is the option B) All the ammonia is consumed.

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Determine the volume occupied by 2.5 mol of a gas at 18 °C if the pressure is 81.8 kPa?
mars1129 [50]

Answer:

74 litre

Explanation:

using ideal gas eqation PV=nRT

here P(pressure)=81.8 kPa =81.8×10^3 Pa

moles=2.5

temperature=273.15+18=291.15K

Gas constant R=8.314m^3-Pa/K-mol

now, V=nRT/P = 8.314×2.5×291.5/81.8×10^3 ≈74litre

✌️;)

3 0
3 years ago
Write the Lewis structure for the following<br> H20<br> So2
Tasya [4]

See the sketch attached.

<h3>Explanation</h3>

The Lewis structure of a molecule describes

  • the number of bonds it has,
  • the source of electrons in each bond, and
  • the position of any lone pairs of electrons.

Atoms are most stable when they have eight or no electrons in their valence shell (or two, in case of hydrogen.)

  • Each oxygen atom contains six valence electrons. It demands <em>two</em> extra electrons to be chemically stable.
  • Each sulfur atom contains six valence electrons. It demands <em>two </em> extra electrons to be chemically stable.
  • Each hydrogen atom demands <em>one</em> extra electron to be stable.

H₂O contains two hydrogen atoms and one oxygen atom. It would take an extra 2 + 2  × 1 = 4 electrons for all its three atoms are stable. Atoms in an H₂O would achieve that need by sharing electrons. It would form a total of 4 / 2 = 2 O-H bonds.

Each O-H bond contains one electron from oxygen and one from hydrogen. Hydrogen has no electron left. Oxygen has six electrons. Two of them have went to the two O-H bonds. The remaining four become 4 / 2 = 2 lone pairs. The lone pairs repel the O-H bonds. By convention, they are placed on top of the two H atoms.

Similarly, atoms in a SO₂ molecule demands an extra 2 × 2 + 2 = 6 electrons for its three atoms to become chemically stable. It would form 6 / 2 = 3 chemical bonds. Loops are unlikely in molecules without carbon. As a result, one of the two O atoms would form two bonds with the S atom while the other form only one.

Atoms are unstable with an odd number of valence electrons. The S atom in SO₂ would have become unstable if it contribute one electron to each of the three bond. It would end up with 3 × 2 + 3 = 9 valence electrons. One possible solution is that it contributes two electrons in one particular bond. One of the three bonds would be a coordinate covalent bond, with both electrons in that bond from the S atom. In some textbooks this type of bonds are also known as dative bonds.

Dots and crosses denotes the origin of electrons in a bond. Use the same symbol for electrons from the same atom. Electrons from the oxygen atoms O are shown in blue in the sketch. They don't have to be colored.

7 0
3 years ago
An herbicide contains only C, H, Cl, and N. The complete combustion of a 200.0 mg sample of the herbicide in excess oxygen produ
MAVERICK [17]

Answer:

%C = 56,1%

%H = 5,5%

%Cl = 27,6%

%N = 10,8%

Explanation:

The moles of CO₂ are the same than moles of C in the herbicide.

Moles of H₂O are ¹/₂ of moles of H in the herbicide.

Moles of CO₂ are obtained using:

n = PV/RT

Where, in STP: P is 1 atm; V is 0,2092L; R is 0,082atmL/molK; T is 273 K

moles of CO₂ are: 9,345x10⁻³ mol≡ mol of C×12,01g/mol = <em>0,1122 g of C ≡ 112,2mg of C</em>

In the same way, moles of H₂O are 5,450x10⁻³mol×2 =0,1090 mol of H×1,01g/mol = <em>0,0110 g of H ≡ 11,0mg of H</em>

As you have 55,14 mg of Cl, the mg of N are:

200,0mg - 112,2 mg of C - 11,0 mg of H - 55,14 mg of Cl = 21,66 mg of N

Thus, precent composition of the herbicide is:

%C = \frac{112,2 mgC}{200,0mg}×100 = 56,1%C

%H = \frac{11,0 mgH}{200,0mg}×100 = 5,5%H

%Cl = \frac{55,14 mgCl}{200,0mg}×100 = 27,6%Cl

%N = \frac{21,66 mgN}{200,0mg}×100 = 10,8%N

I hope it helps!

3 0
3 years ago
Pls help me 20 points ty
qaws [65]

Answer:

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Explanation:

6 0
3 years ago
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A metal hammer has been lying in the sunlight on a hot day. When you pick up the hammer, it feels very warm in your hand. Can yo
tangare [24]

Answer:

When the hammer is in the sun, heat flows by radiation

When you pick up the hammer, heat flows by conduction

Explanation:

As the hammer lies in the sun, heat is transferred to the hammer by radiation. Heat energy reaches the earth from the sun by radiation. Radiation is a mode of beat transfer in which heat is transferred without a material medium.

When you pick up the hammer, heat flows to your hand by conduction because your body is a conductor of heat.

3 0
3 years ago
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