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2 years ago

The unit of measurement “mal” describes what property of a substance?

Chemistry

1 answer:

zheka24 [161]2 years ago

3 0

A mal describes volume. it equals nearly 2 L

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6.02 Ionic and covalent bonds.

Ivan

Convalent Bond energy is low

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3 years ago

What is the composition of the nuclei modeled by these symbols? How many protons and neutrons?

gayaneshka [121]

There are six protons and eight neutrons present in the carbon atom as shown.

<h3>What is the nucleus?</h3>

The nucleus of an atom consists of its protons and its neutrons. The protons are positively charged while the neutrons have no charge.

From the symbol of the element as shown in the question, we can see that there are six protons and eight neutrons present.

Learn more about nucleus of atoms:brainly.com/question/10658589

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6 0

1 year ago

A gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure of 32.5 kPa. If Po2 =

HACTEHA [7]

Answer:

A gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure of 32.5 kPa.

<u>The pressure for oxygen is 3 kPa</u>

Explanation:

According to Dalton's Law of Partial Pressure total exerted by the mixture of non-reacting gases is equal to sum of the partial pressure of each gas.

$P_{total}=P_{1}+P_{2}+P_{3}$

So,

For , a gas mixture containing oxygen, nitrogen, and carbon dioxide has a total pressure:

$P_{total}=P_{O_{2}}+P_{N_{2}}+P_{CO_{2}}$

$P_{total} = 32.5kPa$

$P_{O_{2}} = 6.5kPa$

$P_{N_{2}} = 23.0kPa$

Insert the values in :

$P_{total}=P_{O_{2}}+P_{N_{2}}+P_{CO_{2}}$

$32.5 kPa = 6.5 kPa + 23.0 kPa +P_{CO_{2}}$

$32.5 kPa = 29.5 kPa +P_{CO_{2}}$

$P_{CO_{2}}= 32.5 - 29.5$

$P_{CO_{2}}= 3kPa$

6 0

2 years ago

You’ve just started a new job in the laboratory of the Food and Drug Administration. Your supervisor asks you to prepare a 1.50-

anastassius [24]

Answer: 118.5 grams

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= moles of solute

$V_s$ = volume of solution in ml = 500 ml

$1.50=\frac{moles\times 1000}{500ml}$

moles = 0.75

moles of solute = $\frac{\text {given mass}}{\text {molar mass}}$

0.75 = $\frac{\text {given mass}}{158g/mol}$

mass of $KMnO_4$ = 118.5 grams

Thus mass of $KMnO_4$ needed to prepare 500 mL of this solution iis 118.5 grams

6 0

2 years ago

C= ( F - 32) / 1.8<br> 86 F = ?

egoroff_w [7]

<em>Hence</em><em>,</em><em> </em><em>84</em><em>°</em><em>F</em><em> </em><em>is</em><em> </em><em>30</em><em>°</em><em>C</em><em> </em><em>in</em><em> </em><em>Celsius</em><em>.</em><em>.</em>

7 0

1 year ago