Science has classified energy into two main forms: kinetic energy and potential energy. In addition, potential energy takes several forms of its own. Kinetic energy is defined as the energy of a moving object.
The mass in grams of butane at standard room temperature is 53.21 grams.
<h3>How can we determine the mass of an organic substance at room temperature?</h3>
The gram of an organic substance at room temperature can be determined by using the ideal gas equation which can be expressed as:
PV = nRT
- Pressure = 1.00 atm
- Volume = 22.4 L
- Rate = 0.0821 atm*L/mol*K
- Temperature = 25° C = 298 k
1 × 22.4 L = n × (0.0821 atm*L/mol*K× 298 K)
n = 22.4/24.4658 moles
n = 0.91556 moles
Recall that:
- number of moles = mass(in grams)/molar mass
mass of butane = 0.91556 moles × 58.12 g/mole
mass of butane = 53.21 grams
Learn more about calculating the mass of an organic substance here:
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Answer:
ΔG = 16.218 KJ/mol
Explanation:
- dihydroxyacetone phosphate ↔ glyceraldehyde-3-phosphate
∴ ΔG° = 7.53 KJ/mol * ( 1000 J / KJ ) = 7530 J/mol
∴ R = 8.314 J/K.mol
∴ T = 298 K
∴ Q = [glyceraldehyde-3-phosphate] / [dihydroxyacetone phosphate]
⇒ Q = 0.00300 / 0.100 = 0.03
⇒ ΔG = 7530J/mol - (( 8.314 J/K.mol) * ( 298 K ) * Ln ( 0.03 ))
⇒ ΔG = 16217.7496 J/mol ( 16.218 KJ/mol )
Answer:I would say 21grams but i am not sure
Explanation:
