A polar covenant bond is likely to form between two atoms that _______

Compare the root mean square speeds of O2 and UF6 at 65 degree Celsius

gayaneshka [121]

<h3>Answer:</h3>

The root mean square speeds of O₂ and UF₆ is 513m/s and 155 m/s respectively.

<h3>Solution and Explanation:</h3>

To find how fast molecules or particles of gases move at a particular temperature, the root mean square speed is calculated.
Root mean square speed of a gas is calculated by using the formula;

$Root mean square=\sqrt{ \frac{3RT}{M}$

Where R is the molar gas constant, T is the temperature and M is the molar mass of gas in Kg.

<h3>Step 1: Root mean square speed from O₂</h3>

Molar mass of Oxygen is 32.0 g/mol or 0.032 kg/mol

Temperature = 65 degrees Celsius or 338 K

Molar gas constant = 8.3145 J/k.mol

$Root mean square speed = \sqrt\frac{(3)(8.3145)(338K)}{0.032}$

$= 513.289 m/s$

<h3>Step 2: Root mean square speed of UF₆ </h3>

The molar mass of UF₆ is 352 g/mol or 0.352 kg/mol

$Root mean square speed = \sqrt\frac{(3)(8.3145)(338K)}{0.352}$

$= 154.762m/s$

Therefore; the root mean square speeds of O₂ and UF₆ is 513m/s and 155 m/s respectively.

7 0

3 years ago

What volume of silver will weigh exactly 2500 g. The density of silver is 10 g/cm3.

zysi [14]

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question we have

$volume = \frac{2500}{10} \\$

Wr have the final answer as

Hope this helps you

7 0

3 years ago

Help!!!!?????????? plssssssss

DIA [1.3K]

Answer: it’s b)

Explanation: that’s the only difference that is listed

4 0

3 years ago

Read 2 more answers

How many moles of NaCl are in 2,719 mL of a 6.32 M solution?

Mademuasel [1]

Answer:

17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.

Explanation:

$Molarity=\frac{\text{Moles of substance}}{\text{Volume of solution in L}}$

We have:

Molarity of the NaCl solution = 6.32 M

Volume of the NaCl solution = 2,719 mL =2,719 × 0.001 L= 2.719 L

1 mL = 0.001 L

Let the moles of NaCl be n.

$6.32 M=\frac{n}{2.719 L}$

$n=6.32M\times 2.719 L=17.18 mol$

17.18 moles of NaCl are in 2,719 mL of a 6.32 M solution.

6 0

4 years ago

Be sure to answer all parts. one of the most important industrial sources of ethanol is the reaction of steam with ethene derive

lions [1.4K]

Answer: 2.17x10⁻³ atm

Explanation:

First, we must write the balanced chemical equation for the process:

C₂H₄(g) + H₂O(g) ⇌ C₂H₅OH(g)

The chemical reactions that occur in a closed container can reach a state of <u>chemical equilibrium</u> that is characterized because the concentrations of the reactants and products remain constant over time. The <u>equilibrium constant</u> of a chemical reaction is the value of its reaction quotient in chemical equilibrium.

The equilibrium constant (K) is expressed as <u>the ratio between the molar concentrations (mol/L) of reactants and products.</u> Its value in a chemical reaction depends on the temperature, so it must always be specified.

<u>We will use the the equilibrium constant Kc of the reaction to calculate partial pressure of ethene.</u> The constant Kc for the above reaction is,

Kc = $\frac{[C_{2} H_{5}OH]}{[H_{2}O][C_{2} H_{4}]}$

According to the law of ideal gases,

PV = nRT

where P, V, n and T are the pressure, volume, moles and temperature of the gas in question while R is the gas constant (0.082057 atm L / mol K) .

We can use the ideal gas law to determine the molar concentrations ([x] = n / V) from the gas pressures of ethanol and water, assuming that all gases involved behave as ideal gases. In this way,

PV = nRT → P = (n/V) RT → P = [x] RT → [x] = P / RT

So,

$[C_{2} H_{5}OH] = \frac{200 atm}{0.082057 \frac{atm L}{mol K} x 600 K } = 4.06 \frac{mol}{L}$

$[H_{2}O] = \frac{400 atm}{0.082057 \frac{atm L}{mol K} x 600 K } = 8.12 \frac{mol}{L}$

So, the molar concentration of ethene (C₂H₄) will be,

$[C_{2} H_{4}] = \frac{[C_{2} H_{5}OH]}{[H_{2}O] x Kc} = \frac{4.06 \frac{mol}{L} }{8.12 \frac{mol}{L}x9.00 x 10^{3} \frac{L}{mol} } = 5.56 x 10^{-5}\frac{mol}{L}$

Then, according to the law of ideal gases,

$P_{C_{2} H_{4}} = [C_{2} H_{4}]RT = 5.56 x 10^{-5} \frac{mol}{L} x 0.082057 \frac{atm L}{mol K} x 600 K = 2.17x10^{-3} atm$

So, when the partial pressure of ethanol is 200 atm and the partial pressure of water is 400 atm, the partial pressure of ethene at 600 K is 2.17x10⁻³ atm.

7 0

3 years ago

A polar covenant bond is likely to form between two atoms that ________.