What jobs involve chesmistry

For each of the following balanced chemical equations, calculate how many moles and how many grams of each product would be prod

natima [27]

Answer:

(a)

Moles of ammonium chloride = 0.5 mole

Mass of ammonium chloride formed = 26.7455 g

(b)

Mole of $CS_2$ = 0.125 mole

Mass = Moles * Molar mass = 0.125 * 76.139 g = 9.52 g

Mole of $H_2S$ = 0.25 mole

Mass = Moles * Molar mass = 0.25 * 34.1 g = 8.525 g

Explanation:

(a)

For the first reaction:-

$NH_3_{(g)}+HCl_{(g)}\rightarrow NH_4Cl_{(s)}$

The mole ratio of the reactants = 1 : 1

0.5 moles of ammonia react with 0.5 moles of hydrochloric gas to give 0.5 moles of ammonium chloride

So, Moles of ammonium chloride formed = 0.5 moles

Molar mass of ammonium chloride = 53.491 g/mol

Mass = Moles * Molar mass = 0.5 * 53.491 g = 26.7455 g

(b)

For the first reaction:-

$CH_4_{(g)}+4S_{(s)}\rightarrow CS_2_{(l)}+2H_2S_{(g)}$

The mole ratio of the reactants = 1 : 4

It means

0.5 moles of methane react with 2.0 moles of sulfur to give 0.5 moles of Carbon disulfide and 1.0 moles of hydrogen sulfide gas.

But available moles of S = 0.5 moles

Limiting reagent is the one which is present in small amount. Thus, S is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

4 moles of S produces 1 mole of $CS_2$

Thus,

0.5 moles of S produces $\frac{1}{4}\times 0.5$ mole of $CS_2$

Mole of $CS_2$ = 0.125 mole

Molar mass of $CS_2$ = 76.139 g/mol

Mass = Moles * Molar mass = 0.125 * 76.139 g = 9.52 g

4 moles of S produces 2 moles of $H_2S$

Thus,

0.5 moles of S produces $\frac{2}{4}\times 0.5$ mole of $H_2S$

Mole of $H_2S$ = 0.25 mole

Molar mass of $H_2S$ = 34.1 g/mol

Mass = Moles * Molar mass = 0.25 * 34.1 g = 8.525 g

7 0

2 years ago

In a reaction A+B--->C, reactant A has 5g of product C has 9g of product. How many grams should reactant B contain?

Rzqust [24]

According to the law of conservation of Mass:

In a chemical reaction mass can neither be created nor be destroyed

So, we can say that: Mass of A + Mass of B = Mass of C

In the given reaction,

One of the reactants weigh 5 grams and another one weighs x grams

The mass of the product of this reaction is 9 grams

Mass of reactant B:

Mass of A + Mass of B = Mass of C

5 + x = 9

x = 4 grams

5 0

2 years ago

What is the temperature of water when baking soda and citric acid is mixed with it?

asambeis [7]

Answer:

brainly.com/question/18996619?answering=true&answeringSource=feedPublic%2FhomePage%2F7

Explanation:

brainly.com/question/18996619?answering=true&answeringSource=feedPublic%2FhomePage%2F7

4 0

2 years ago

In which of the following equilibrium systems will an increase in the volume cause the equilibrium to shift away from the reacta

Alenkinab [10]

Answer: 2NOBr(g) ⇌ 2NO(g) + Br2(g)

Explanation: For volume changes in equillibrium, the following are to be taken into consideration:

Volume changes have no effect on equillibrium system that contains solid or aqueous solutions.
An increase in volume of an equilibrium system will shift to favor the direction that produces more moles of gas.
A decrease in volume of an equilibrium system will shift to favor the direction that produces less moles of gas.
Volume changes will have no effect on the equillibrium system if there is an equal number of moles on both sides of the reaction.

2NOBr(g) ⇌ 2NO(g) + Br2(g) is the equillibrium system because there are more moles of products,therefore an increase in the volume of the reaction will shift to the right and produce more moles of products. Also both reactants and products exist in the gaseous state and does not have equal number of moles.

5 0

2 years ago

Mention any two uses of oxygen gas.

Elodia [21]

Answer:

steel, plastics

<h3>Explanation:</h3>

Hope it helps!

3 0

3 years ago