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Helga [31]
3 years ago
15

During the phosphatase experiment you will use a 1% w/v of phenolphthalein di-phosphate (PPP). How much PPP do you need to make

500ml of the solution if you only have 25g and you know that the MW of PPP is 478 g/mole?
Chemistry
1 answer:
MrMuchimi3 years ago
7 0

Answer:

To make 500 mL of a solution of PPP 1% w/v you need 5g

Explanation:

A percent w/v solution is calculated with the following formula using the gram as the base measure of weight (w):

% w/v = g of solute/ mL of solution × 100

A 1% w/v means that you have 1 g of PPP per 100 mL of solution

Thus, if you need to make 500 mL of solution you will need 5 g of PPP.

I hope it helps!

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if you were one of the immigrants, would you willingly submit to have yourself undergone x-ray to prove yourself being a minor?
MariettaO [177]

Answer:

I'm pretty sure this is a question about your opinion so there is no wrong answer! Just think about the question and if you were in those shoes. There is no right or wrong answer! :)

Explanation:

3 0
2 years ago
Which pair of elements form an ionic bond?
Anastasy [175]

Answer:

As an example I can say sodium (Na) and chlorine (Cl).

Explanation:

An ionic bond occurs when a metal element reacts with a nonmetal element. Therefore in the answer given above the Na is metal and Cl is nonmetal and they form a molecule through ionic bonding.

3 0
3 years ago
Students asked to measure the temperature of a reaction beaker recorded the following temperatures. 103.7°C, 108.4°C, 105.8°C, 1
Nata [24]

There are two terms

a) accuracy : it relates to the exactness of an answer that how an answer is close to the actual answer or actual reading

So 104.6 is accurate

b) Precision : This is related to the closeness of different readings with each other

The first reading is 103.7 and the second one is 108.4  so the second reading is quite different from the first reading so it cannot be called as precised

Again 105.8 has good difference from the second reading hence again this is not precised

However the last reading 104.6 is quite near to 105.8 so 104.6 can be called as precise


6 0
3 years ago
Read 2 more answers
50.0 ml of 0.010m naoh was titrated with 0.50m hcl using a dropper pipet. if the average drop from the pipet has a volume of 0.0
creativ13 [48]

25 drops of acid is required to neutralize the 50.0 ml of 0.010m of NaOH in the experiment.

The equation of the reaction is;

NaOH(aq) + HCl(aq) ---------> NaCl(aq) + H2O(l)

We can use the titration formula;

CAVA/CBVB = NA/NB

CA= concentration of acid

VA = volume of acid

CB = concentration of base

VB = volume of base

NA = number of moles of acid

NB = number of moles of base

CB = 0.010 M

VB = 50.0 ml

CA = 0.50 M

VA = ?

NA = 1

NB = 1

Substituting values;

CAVANB = CBVBNA

VA =  0.010 ×  50.0 × 1/ 0.50 × 1

VA = 1 ml

Since the total volume of acid used is 1 ml and each drop contains 0.040 ml

The number of drops required is 1ml/0.040 ml = 25 drops

Learn more: brainly.com/question/1527403

4 0
2 years ago
Please i need help ……
nasty-shy [4]

Answer:

H2

Explanation:

(l) means liquid

(s) means solid

(g) means gaseous

I hope this helped [:

3 0
2 years ago
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