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weqwewe [10]
3 years ago
13

If you start with 64g of a radioactive element how many half-lives would occur before 8g remain?

Chemistry
1 answer:
Nonamiya [84]3 years ago
3 0

Answer:

3 half-lives

Explanation:

The half-life is the time that it takes to a radioactive element to decay to half of its initial amount.

Let's suppose we start with 64 g of the radioactive element.

  • After 1 half-life, the mass of the element will be 32 g.
  • After 2 half-lives, the mass of the element will be 16 g.
  • After 3 half-lives, the mass of the element will be 8 g.
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If 1.8 L of water is added to 2.5L of a 7.0 M KOH solution, what is the molarity of the new solution
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Answer : The molarity of the new solution is, 4.069 M

Solution : Given,

Molarity of KOH solution = 4 M

Volume of KOH solution = 2.5 L

Volume of water added = 1.8 L

First we have to calculate the volume of new solution.

Volume of new solution = volume of KOH solution + volume of water added

Volume of new solution = 2.5 L + 1.8 L = 4.3 L

Now we have to calculate the molarity of the new solution.

Formula used :

M_1V_1=M_2V_2

where,

M_1 = molarity of KOH solution

M_2 = molarity of new solution

V_1 = volume of KOH solution

V_2 = volume of new solution

Now put all the given values in the above formula, we get the molarity of the new solution.

(7M)\times (2.5L)=M_2\times (4.3L)

M_2=4.069M

Therefore, the molarity of the new solution is, 4.069 M

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Fe2O3 + _H2SO4 → _Fe2(SO4)3 + __H2O what are the coefficients
lbvjy [14]

Answer:

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Now we need the same amount of H⁺ on each side

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