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weqwewe [10]
2 years ago
13

If you start with 64g of a radioactive element how many half-lives would occur before 8g remain?

Chemistry
1 answer:
Nonamiya [84]2 years ago
3 0

Answer:

3 half-lives

Explanation:

The half-life is the time that it takes to a radioactive element to decay to half of its initial amount.

Let's suppose we start with 64 g of the radioactive element.

  • After 1 half-life, the mass of the element will be 32 g.
  • After 2 half-lives, the mass of the element will be 16 g.
  • After 3 half-lives, the mass of the element will be 8 g.
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Calculate the mass of Na2O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reacti
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Answer:

The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.

Explanation:

You know  the balanced reaction:

4 NA + O₂ ⟶ 2 Na₂O

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) react and are produced:

  • Na: 4 moles
  • O₂: 1 mole
  • Na₂O: 2 moles

Being:

  • Na: 23 g/ole
  • O: 16 g/mole

the molar mass of the compounds participating in the reaction is:

  • Na: 23 g/mole
  • O₂: 2*16 g/mole= 32 g/mole
  • Na₂O: 2*23 g/mole +16 g/mole=  62 g/mole

Then by stoichiometry of the reaction they react and are produced:

  • Na: 4 moles* 23 g/mole= 92 g
  • O₂: 1 mole*32  g/mole= 32 g
  • Na₂O: 2 moles* 62 g/mole= 124 g

Then you can apply the following rule of three: if 92 grams of Na produce 124 grams of Na₂O, 4 grams of Na, how much mass of Na₂O does it produce?

massofNa_{2}O =\frac{4 grams of Na*124 gramsofNa_{2}O }{92 grams of Na}

mass of Na₂O=5.39 g

<em><u>The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.</u></em>

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Why do the two electrons spend their time equally between both hydrogen atoms? In other words, why can’t one hydrogen just take
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Because it is a covalent bond meaning that they share the electrons to achieve full valence.
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