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3 years ago

HELP ASAP Pleaseeeeeeeeee

Chemistry

2 answers:

Radda [10]3 years ago

7 0

Answer:

avery

Explanation:

kykrilka [37]3 years ago

6 0

Answer:

avery is more faster.

Explanation:

reese's speed = 10/5 = 2km/hr

reese's speed = 10/5 = 2km/hravery's speed = 15/5 = 3km/hr

reese's speed = 10/5 = 2km/hravery's speed = 15/5 = 3km/hrby seeing their speeds we can easily tell that avery is more faster than reese ... 

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What is the molarity of a solution that has 2.52 grams of NaCO3 dissolved to

sammy [17]

Answer:

Explanation:

2.52g/ 0.125L= 20.16M

5 0

2 years ago

Consider the following reaction at a high temperature. Br2(g) ⇆ 2Br(g) When 1.35 moles of Br2 are put in a 0.780−L flask, 3.60 p

UNO [17]

Answer : The equilibrium constant $K_c$ for the reaction is, 0.1133

Explanation :

First we have to calculate the concentration of $Br_2$ .

$\text{Concentration of }Br_2=\frac{\text{Moles of }Br_2}{\text{Volume of solution}}$

$\text{Concentration of }Br_2=\frac{1.35moles}{0.780L}=1.731M$

Now we have to calculate the dissociated concentration of $Br_2$ .

The balanced equilibrium reaction is,

$Br_2(g)\rightleftharpoons 2Br(aq)$

Initial conc. 1.731 M 0

At eqm. conc. (1.731-x) (2x) M

As we are given,

The percent of dissociation of $Br_2$ = $\alpha$ = 1.2 %

So, the dissociate concentration of $Br_2$ = $C\alpha=1.731M\times \frac{1.2}{100}=0.2077M$

The value of x = 0.2077 M

Now we have to calculate the concentration of $Br_2\text{ and }Br$ at equilibrium.

Concentration of $Br_2$ = 1.731 - x = 1.731 - 0.2077 = 1.5233 M

Concentration of $Br$ = 2x = 2 × 0.2077 = 0.4154 M

Now we have to calculate the equilibrium constant for the reaction.

The expression of equilibrium constant for the reaction will be :

$K_c=\frac{[Br]^2}{[Br_2]}$

Now put all the values in this expression, we get :

$K_c=\frac{(0.4154)^2}{1.5233}=0.1133$

Therefore, the equilibrium constant $K_c$ for the reaction is, 0.1133

7 0

3 years ago

What changes are observed on heat capacity ratio and output temperatures by increasing the specific heat capacity of both the fl

BlackZzzverrR [31]

Answer:

b- The heat capacity ratio increases but output temperature don’t change

Explanation:

The heat capacity is the amount of energy required to raise the temperature of a body, by 1 degree. On the other hand, the specific heat capacity is the amount of heat required to raise the temperature of a of unit mass of a material by 1 degree.

Heat capacity is an extensive property meaning its value depends on the amount of material. Specific heat capacity is found by dividing heat capacity by the mass of the sample, thus making it independent of the amount (intensive property). So if the specific heat capacity increases and the mass of the sample remains the same, the heat capacity must increase too. Because of that options c and d that say that heat capacity reamins same are INCORRECT.

On the other hand, in which has to be with options a and b both say that the heat capacity increases which is correct, but about the output temperatures what happens is that if we increase the specific heat capacity of both fluids that are involved in a process of heat exchange in the same value, the value of the output temperatures do not change so only option a is CORRECT.

8 0

3 years ago

What best describes the degree to which a material can transmit Heat A:melting point B:boiling point C: thermal conductivity D:

Oduvanchick [21]

Your answer is going to be C

7 0

3 years ago

Read 2 more answers

A gas with 4.0 atmospheres of pressure has a temperature of 27°C.

Gala2k [10]

Answer:

7.462

Explanation:

Well, every time that the tempurature is increased, the atmspheric pressure is increased by 0.574%. This would then mean that you would have 0.574 times

13. That would then equal 7.462. I hope this helps.

6 0

2 years ago