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densk [106]
3 years ago
6

The pattern in a simple____ truss is a zigzag

Engineering
1 answer:
liberstina [14]3 years ago
6 0

Answer:

Bridge

Explanation:

A common, simply bridge truss is the zigzag.

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The pump of a water distribution system is powered by a 15-kW electric motor whose efficiency is 90 percent. The water flow rate
wariber [46]

Answer:

Mechanical power of pump is 74.07%.    

Explanation:

Power of motor = 15 KW

Efficiency of motor= 90%

So the actual power(P) supplied by motor = 0.9 x 15 KW

P=13.5 KW

Water flow rate = 50 L/s

Volume flow rate = 50 L/s

We know that

1000\ L/s=1\ m^3/s

So

Volume\ flow \rate =0.05\ m^3/s

We know that pump is an open system and work input for open system can be calculated as

W=VΔP

ΔP is the pressure difference

V is the volume flow rate

So by putting the values

W=0.05 (300-100)            (here ΔP=300 - 100=200 KPa)

W=10 KW    

So mechanical power of pump

\eta =\dfrac{W}{P}        

\eta =\dfrac{10}{13.5}    

η =0.7407

Mechanical power of pump is 74.07%.    

6 0
3 years ago
Could a volcanic eruption suddenly bury a city and its inhabitants? (Plz explain to me)
andrezito [222]
Yes a volcanic eruption can suddenly bury a city ! if you look up some stuff on pompeii you can learn more
7 0
3 years ago
Consider a voltage v = Vdc + vac where Vdc = a constant and the average value of vac = 0. Apply the integral definition of RMS t
Anna11 [10]

Answer:

Proof is as follows

Proof:

Given that , V = V_{ac} + V_{dc}

<u>for any function f with period T, RMS is given by</u>

<u />RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[f(t)]^{2} } \, dt  }<u />

In our case, function is V = V_{ac} + V_{dc}

RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[V_{ac} + V_{dc}]^{2} } \, dt  }

Now open the square term as follows

RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[V_{ac}^{2} + V_{dc}^{2} + 2V_{dc}V_{ac}] } \, dt  }

Rearranging  terms

RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {V_{dc}^{2}  } \, dt  + \frac{1}{T}\int\limits^T_0 {V_{ac}^{2}  } \, dt  + \frac{1}{T}\int\limits^T_0 {2V_{dc}V_{ac}  } \, dt  }

You can see that

  • second term is square of RMS value of Vac
  • Third terms is average of VdcVac and given is that                      average of  V_{ac}V_{dc} = 0

so

RMS = \sqrt{\frac{1}{T}TV_{dc}^{2}   + [RMS~~ of~~ V_{ac}]^2 }

RMS = \sqrt{V_{dc}^{2}   + [RMS~~ of~~ V_{ac}]^2 }

So it has been proved that given expression for root mean square (RMS) is valid

7 0
3 years ago
Admission to an aquarium is $14 per person. There is also an IMAX theatre in the building, which charges $8 per ticket for a 3D
adoni [48]

Answer:

x=14a+8b+16.5c

Explanation:

x=total cost

a=number of people in just aquarium

b=number of people in just IMAX

c=number of people in both

c=(14+8)×0.75=22×0.75=16.5

8 0
3 years ago
Chlorine is one of the important commodity chemicals for the global economy. Before the advent of large scale
artcher [175]

The composition of gas in the feed, the percentage conversion and the

theoretical yield are combined to give the product stream composition.

Response:

The composition of gas in the product stream are;

  • HCl: 0.4 kmol/h, Cl₂: 1.6 kmol/h, H₂O: 1.6 kmol/h, O₂: 0.5 kmol/h

<h3>How can percentage conversion give the contents of the product stream?</h3>

The amount of oxygen used = 30% exceeding the theoretical amount

Number of moles of hydrochloric acid = 4 kmol/h

Percentage conversion = 80%

Required:

The composition of the gas in the product feed.

Solution;

The given reaction is; 4HCl + O₂ \longrightarrow 2Cl₂ + 2H₂O

Percentage \ conversion = \mathbf{ \dfrac{Moles \ of \ limiting \ reactant \ reacted}{Moles \  of \ limiting \ reactant \ supplied \ in \ the \, feed}}

Which gives;

80 \% = \mathbf{ \dfrac{Moles \ of \ limiting \ reactant \ reacted}{4 \, kmol/h}}

Moles of limiting reactant reacted = 4 kmol/h × 0.80 = 3.6 kmol/h

Which gives;

Number of moles of HCl in the stream = 4 kmol/h - 3.6 kmol/h = 0.4 kmol/h

Number of moles of Cl₂ produced = 2 kmol/h × 0.8 = 1.6 kmol/h

Similarly;

Number of moles of H₂O produced = 2 kmol/h × 0.8 = 1.6 kmol/h

Number of moles of O₂ in the product stream = 30% × 1 kmol/h + 20% × 1 kmol/h = 0.5 kmol/h

The composition of the production stream is therefore;

  • <u>HCl: 0.4 kmol/h</u>
  • <u>Cl₂: 1.6 kmol/h</u>
  • <u>H₂O: 1.6 kmol/h</u>
  • <u>O₂: 0.5 kmol/h</u>

Learn more about theoretical and actual yield here:

brainly.com/question/14668990

brainly.com/question/82989

7 0
3 years ago
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