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Dennis_Churaev [7]
3 years ago
7

Chlorine is one of the important commodity chemicals for the global economy. Before the advent of large scale

Engineering
1 answer:
artcher [175]3 years ago
7 0

The composition of gas in the feed, the percentage conversion and the

theoretical yield are combined to give the product stream composition.

Response:

The composition of gas in the product stream are;

  • HCl: 0.4 kmol/h, Cl₂: 1.6 kmol/h, H₂O: 1.6 kmol/h, O₂: 0.5 kmol/h

<h3>How can percentage conversion give the contents of the product stream?</h3>

The amount of oxygen used = 30% exceeding the theoretical amount

Number of moles of hydrochloric acid = 4 kmol/h

Percentage conversion = 80%

Required:

The composition of the gas in the product feed.

Solution;

The given reaction is; 4HCl + O₂ \longrightarrow 2Cl₂ + 2H₂O

Percentage \ conversion = \mathbf{ \dfrac{Moles \ of \ limiting \ reactant \ reacted}{Moles \  of \ limiting \ reactant \ supplied \ in \ the \, feed}}

Which gives;

80 \% = \mathbf{ \dfrac{Moles \ of \ limiting \ reactant \ reacted}{4 \, kmol/h}}

Moles of limiting reactant reacted = 4 kmol/h × 0.80 = 3.6 kmol/h

Which gives;

Number of moles of HCl in the stream = 4 kmol/h - 3.6 kmol/h = 0.4 kmol/h

Number of moles of Cl₂ produced = 2 kmol/h × 0.8 = 1.6 kmol/h

Similarly;

Number of moles of H₂O produced = 2 kmol/h × 0.8 = 1.6 kmol/h

Number of moles of O₂ in the product stream = 30% × 1 kmol/h + 20% × 1 kmol/h = 0.5 kmol/h

The composition of the production stream is therefore;

  • <u>HCl: 0.4 kmol/h</u>
  • <u>Cl₂: 1.6 kmol/h</u>
  • <u>H₂O: 1.6 kmol/h</u>
  • <u>O₂: 0.5 kmol/h</u>

Learn more about theoretical and actual yield here:

brainly.com/question/14668990

brainly.com/question/82989

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A motorist is driving his car at 60km/hr when he observes that a traffic light 250m ahead turns red. The traffic light is
Alecsey [184]

Explanation:

Okay soo-

Given-

u = 60 km/hr = 60×1000/3600=50/3 m/s

t = 20 s

s = 250 m

a = ?

v = ?

Solution -

Here, acceleration is uniform.

(a) According to 2nd kinematics equation,

s = ut + ½at^2

250 = 50/3 ×20 + 0.5×a×20×20

250-1000/3=200a

(750-1000)/3=200a

a = -250/(3×200)

a = -5/12

a = 0.4167 m/s^2

The required uniform acceleration of the car is 0.4167 m/s^2.

(b) According to 1st kinematics equation

v = u + at

v = 50/3 + (-5/12)×20

v = 50/3-25/3

v = 25/3

v = 8.33 m/s

The speed of the car as it passes the traffic light is 8.33 m/s.

Good luck!

5 0
2 years ago
Use Excel, MatLab or a similar program to plot carrier thermal velocity as a function of temperature for both electrons and hole
Sidana [21]

Answer:

Solution 2:

The thermal energy of any particle is given as = \frac{1}{2}mv^{2}

where m= Effective mass of the particle,

v= Velocity of the particle

The average kinetic energy is given as =  \frac{3}{2}KT,

where K= Boltzmann Constant

T= Temperautre of the particle

At equilibrium,

1/2 mv² =  3/2 KT

Hence, v= \sqrt{\frac{3KT}{m}}

As, effective mass ratio is calculated with respect to rest mass of electron,

melectron = 0.11 * 9.11 *10-31 kg

mhole =  0.35 *9.11 *10-31 kg

K = 1.38 × 10-23 m2 kg s-2 K-1

Plotting, over a range of temperature of 0 K to 400 K, we obtain the attached Graphs (attached).

Solution 3:

The above two curves plotted are not identical as seen. From the same value of Temperature, and under identical conditons, the Thermal velocity solely depends on effective mass ratio. And it is inversely proportional to effective mass ratio. More the effective mass ratio, less the thermal velocity and flatter the slope of the curve and vice versa. As, the mass ratio of holes is more than that of electrons, the curve of electrons has a steeper slope than that of holes. Hence, the curves are not just identical.

8 0
3 years ago
What is used to measure alcohol in the blood
Natali5045456 [20]

Answer:

your doctor uses a needle to take blood from your arm and measure the level of alcohol

Explanation:  there are also other tests such as urine test and breathalyzer tests

5 0
3 years ago
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9. An embankment having a volume of 320,000 yd is to be constructed from local borrow. The dry unit weight and moisture content
tatuchka [14]

Answer:

correct option is (B) 315,500

Explanation:

given data

volume = 320,000 yd³ = 8640000 ft³

dry unit weight = 106 pcf

moisture content = 18.2%

total unit weight = 122 pcf

moisture content = 16.7%

to find out

volume of borrow lyd needed

solution

first we get here weight of material that is

weight = volume × unit weight

weight = 8640000 ×  122

weight = 1054080000 lb

that weight is weight of water + weight of solid so

0.167 × weight is weight of water + weight of solid ) = 1054080000 lb

and weight of solid = \frac{1054080000}{1.167}

weight of soil solid is = 903239075 pound

and weight of water = 150840925 pound

so volume of soil = 903239075 ÷ 106 lb/ft³ = 8521123.34 ft³

and volume required =  8521123.34 ft³ ÷ 27 ft³ =  315597.161 yd³

volume required = 315500 yd³

so correct option is (B) 315,500

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