Answer:
Modulus of resilience will be ![3216942.308j/m^3](https://tex.z-dn.net/?f=3216942.308j%2Fm%5E3)
Explanation:
We have given yield strength ![\sigma _y=818MPa](https://tex.z-dn.net/?f=%5Csigma%20_y%3D818MPa)
Elastic modulus E = 104 GPa
We have to find the modulus
Modulus of resilience is given by
Modulus of resilience
, here
is yield strength and E is elastic modulus
Modulus of resilience
Answer:
Explanation:
The detailed steps and appropriate calculation with analysis is as shown in the attachment.
Answer:
Qx = 9.10
m³/s
Explanation:
given data
diameter = 85 mm
length = 2 m
depth = 9mm
N = 60 rev/min
pressure p = 11 ×
Pa
viscosity n = 100 Pas
angle = 18°
so Qd will be
Qd = 0.5 × π² ×D²×dc × sinA × cosA ..............1
put here value and we get
Qd = 0.5 × π² × ( 85
)²× 9
× sin18 × cos18
Qd = 94.305 ×
m³/s
and
Qb = p × π × D × dc³ × sin²A ÷ 12 × n × L ............2
Qb = 11 ×
× π × 85
× ( 9
)³ × sin²18 ÷ 12 × 100 × 2
Qb = 85.2 ×
m³/s
so here
volume flow rate Qx = Qd - Qb ..............3
Qx = 94.305 ×
- 85.2 ×
Qx = 9.10
m³/s
Answer:
The correct option is;
Materials and Components
Explanation:
The efficiency of fluid power is influenced by the components and the materials used to deliver the power of the fluid as such fluid power control are focused on
1) Advances in fluid power
2) Making use of the advantages
3) Making use of the other externally available technological advantages
4) Giving allowance for disadvantages
Areas of interest in advances in fluid power are;
a. Computer optimized flow
b. The use of new and improved materials/coatings
c. The use of components that save energy, such as intelligent supply pressure adapting systems