2 days late, but the answer is no solution. solving a system of equations means finding where they intersect, but by looking at these equations, you know that they never intersect--they're parallel.
they share a slope (2), making them either parallel or "the same line", but the different x-intercepts (9 and -9) mean that they're different lines. they have no solution, or no intersection point, because they're parallel lines.
Unfortunately, I don’t knooow :(
Answer:
4, 2, 9, 3. They all work out
Step-by-step explanation:
If you need more help just lemme know! :))
Answer:
174
Step-by-step explanation:
thanks for the help guys
Answer:
- r(0) = <0, 100> . . . . . . . .meters
- r'(0) = <7.071, 7.071> . . . . meters per second
Step-by-step explanation:
<u>Initial Position</u>
The problem statement tells us we're measuring position from the ground at the base of the building where the projectile was launched. The initial horizontal position is presumed to be zero. The initial vertical position is said to be 100 meters from the ground, so (in meters) ...
r(0) = <0, 100>
<u>Initial Velocity</u>
The velocity vector resolves into components in the horizontal direction and the vertical direction. For angle α from the horizontal, the horizontal component of velocity is v₁·cos(α), and the vertical component is v₁·sin(α). For v₁ = 10 m/s and α = π/4, the initial velocity vector (in m/s) is ...
r'(0) = <10·cos(π/4), 10·sin(π/4)>
r'(0) ≈ <7.071, 7.071>
