How many grams of magnesium nitride is required to produce 25.00 g of magnesium hydroxide?
1 answer:
Answer:
25 grams of Mg(OH)2 will be produced by 14.424 gram of Mg3N2
Explanation:
The balanced equation is
Mg3N2 + 6H2O -> 3Mg(OH)2 + 2NH3
Molecular weight of magnesium nitride = 100.9494 g/mol
Molecular weight of magnesium hydroxide = 58.3197 g/mol
one mole of Mg3N2 produces three moles of 3Mg(OH)2
100.9494 g/mol of Mg3N2 produces 3* 58.3197 g/mol of Mg(OH)2
1 gram of Mg3N2 produces
grams of Mg(OH)2
Or 1.733 grams of Mg(OH)2 will be produced by 1 gram of Mg3N2
25 grams of Mg(OH)2 will be produced by 14.424 gram of Mg3N2
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Answer:
Explanation:
In Polystrene, the molecular formula for the repeat unit = ;
and the atomic weights of Carbon C = 12.01 g/mol
For Hydrogen, it is 1.01 g/mol
Hence, the repeat unit molecular weight is:
m = 8 (12.01 g/mol)+8(1.01 g/mol)
m = 96.08 g/mol + 8.08 g/mol
m = 104.16 g/mol
The degree of polymerization = no-average molecular weight/repeat unit molecular weight.
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