Answer: 0.17M
Explanation:
The equation for the reaction is :
2HNO3 + Ba(OH)2 —> Ba(NO3)2 + 2H2O
From the balanced equation, we obtain :
nA = mole of acid = 2
nB = mole of the base = 1
From the question, we obtain:
Va = Vol. Of acid = 0.105L
Ma = conc. Of acid =?
Vb = Vol of base = 35.7 mL = 0.0357L
Mb = conc. of base = 0.25M.
We solve for the conc. of the acid using:
MaVa / Mb Vb = nA / nB
(Ma x 0.105) / (0.25x0.0357) = 2
Cross multiply to express in linear form. We have:
Ma x 0.105 = 0.25 x 0.0357 x 2
Divide both side by 0.105. We have
Ma = (0.25 x 0.0357 x 2) / 0.105
Ma = 0.17M
Therefore the concentration of the acid(HNO3) is 0.17M
Answer:
See explanation
Explanation:
Electrons transition between energy levels in an atom due to gain or loss of energy. An electron may gain energy and move from its ground state to one of the accessible excited states. The electron quickly returns to ground state, emitting the energy previously absorbed as a photon of light. The wavelength of light emitted is measured using powerful spectrometers.
Atoms can be excited thermally or by irradiation with light of appropriate frequency.
Answer:

Explanation:
We are asked to find how many moles of sodium carbonate are in 57.3 grams of the substance.
Carbonate is CO₃ and has an oxidation number of -2. Sodium is Na and has an oxidation number of +1. There must be 2 moles of sodium so the charge of the sodium balances the charge of the carbonate. The formula is Na₂CO₃.
We will convert grams to moles using the molar mass or the mass of 1 mole of a substance. They are found on the Periodic Table as the atomic masses, but the units are grams per mole instead of atomic mass units. Look up the molar masses of the individual elements.
- Na: 22.9897693 g/mol
- C: 12.011 g/mol
- O: 15.999 g/mol
Remember the formula contains subscripts. There are multiple moles of some elements in 1 mole of the compound. We multiply the element's molar mass by the subscript after it, then add everything together.
- Na₂ = 22.9897693 * 2= 45.9795386 g/mol
- O₃ = 15.999 * 3= 47.997 g/mol
- Na₂CO₃= 45.9795386 + 12.011 + 47.997 =105.9875386 g/mol
We will convert using dimensional analysis. Set up a ratio using the molar mass.

We are converting 57.3 grams to moles, so we multiply by this value.

Flip the ratio so the units of grams of sodium carbonate cancel.




The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we found that is the thousandth place. The 6 in the ten-thousandth place to the right tells us to round the 0 up to a 1.

There are approximately <u>0.541 moles of sodium carbonate</u> in 57.3 grams.
Answer:
A ) 1, 2 and 3
Explanation:
1 ) is correct because,
K donates 1 electron
F gain 1 electron from K.
If donating and gaining of electrons takes place between two electron, then type of compound formed is ionic.
2 ) is correct because,
K + F -----> KF
3 ) is correct because,
KF is soluble in cold water; very soluble in hot water.