Answer:
0,218 moles
Explanation:
I will first explain how many liters is 256ml, that is 0,256 l.
because the m stands for milli which is a factor of 1000 -> (256 ml / 1000 = 0,256 l)
To calculate the amount of moles you multiply the volume with the concentration. So 0,256l x 0,855M = 0,218 moles.
PbI(ii) ionization in the solution of PBI(ii) into water is:
<span>PbI</span>₂(solution) <==> Pb₂⁺ + 2I⁻
If the conc. of PbI(ii) in the sol. is xM then the conc. of Lead(ii) will be x M and conc. of iodide will be 2 x M.
Therefore,
<span>Ksp=<span>[Pb</span></span>²⁺][I-]²
Plugging the values:
1.4×10⁻⁸ = x ⋅ (2x)²
1.4×10⁻⁸ = 4x³
x³ = {1.4×10⁻⁸}÷4
x³ = 0.35 x 10⁻⁸
or
x³ = 3.5 x 10⁻⁹
x = 1.51 x 10⁻³
Hence,
Concentration of iodide ions in the solution:
2x = 3.02 x 10⁻³
It has 4 valence electron, all of which are needed to bond with nearest neighbors
1,2-dichloroethane of density 1.23 g/ml would settle down an aqueous solution.
<h3>Density:</h3>
Knowing whether the aqueous layer is above or below the organic layer in the separatory funnel is crucial since it determines which layer is ultimately kept and discarded. Because immiscible solvents have different densities, they will stack on top of one another. The less-dense solution will rest on top, and the more dense one will rest at the bottom.
Due to their low density of less than 1 g/mL, the majority of non-halogenated organic solvents will float on top of an aqueous solution (if they are immiscible). One significant exception is that halogenated solvents will sink below aqueous solutions because they are denser than water (having densities greater than 1 g/mL). Except for halogenated solvents like dichloromethane, which are usually on the bottom, most organic solvents, such as diethyl ether, are on top.
Learn more about aqueous layer here:
brainly.com/question/14356327
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Answer:
1700 kj
Explanation:
The given reaction is exothermic reaction.
Exothermic reaction:
The type of reactions in which energy is released are called exothermic reactions.
In this type of reaction energy needed to break the bonds are less than the energy released during the bond formation.
For example:
Chemical equation:
C + O₂ → CO₂
ΔH = -393 Kj/mol
it can be written as,
C + O₂ → CO₂ + 393 Kj/mol
Chemical equation:
2Al + Fe₂O₃ → Al₂O₃ + 2Fe + 850 Kj
when one mole of Fe₂O₃ react 850 kj energy is produced.
when 2 moles react,
2 × 850 kj = 1700 kj