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2 years ago

Pls help!!!!!

Chemistry

2 answers:

umka2103 [35]2 years ago

7 0

The exact positions of the electrons in an atom cannot be determined because electrons are always .

erica [24]2 years ago

3 0

Answer:

moving i think! Hope this helps

Explanation:

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Which of the following has the most stable nucleus? Fe He U B

Harlamova29_29 [7]

Answer:

Explanation:

Ferrum [Iron] has the most stable nucleus because of binding energy per nucleon. Although Uranium is another possibility, in this case, it is more radioactive than Iron. It disintegrates very swiftly that all is done so, just to achieve stability.

I hope this helps you out alot, and as always, I am joyous to assist anyone at any time.

3 0

2 years ago

True or false: chemical reactions are usually written left to right

nika2105 [10]

Answer:

true. e.g

iron+water+oxygen->hydratedironoxide

8 0

1 year ago

Read 2 more answers

I need help on thiss

Sergio039 [100]

The reaction is not balanced

<h3>Further explanation</h3>

Given

Reaction

2Fe(s)+3O₂(g)⇒2Fe₂O₃(s)

Required

The number of atoms

Solution

In a balanced chemical equation, the number of atoms in the compound that reacts (the reactants and products) will have the same number

Reactants : Fe(s)+O₂(g)

Fe = 2 atoms

O = 3 x 2 = 6 atoms

Products : Fe₂O₃(s)

Fe = 2 x 2 = 4 atoms

O = 2 x 3 = 6 atoms

The reaction is not balanced because the number of Fe atoms is not the same

The balanced reaction should be:

4Fe(s)+3O₂(g)⇒2Fe₂O₃(s)

8 0

2 years ago

Below are the reduction half reactions for chemolithoautotrophic nitrification, where ammonia is a source of electrons and energ

SSSSS [86.1K]

Answer: The molecules of oxygen gas that will be reduced to water are 42 molecules

Explanation:

We are given:

$E^o_{(NO_2^-/NH_4)}=-0.41V\\E^o_{(O_2/H_2O)}=0.82V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, oxygen will undergo reduction reaction will get reduced.

$NH_4$ will undergo oxidation reaction and will get oxidized.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

The half reactions follows:

Oxidation half reaction: $NH_4\rightarrow NO_2^-+6e^-$ ( × 4)

Reduction half reaction: $O_2+4e^-\rightarrow 2H_2O$ ( × 6)

Overall reaction: $4NH_4+6O_2\rightarrow 4NO_2^-+12H_2O$

We are given:

Molecules of $NH_4$ = 28

By Stoichiometry of the reaction:

4 molecules of $NH_4$ reacts with 6 molecules of oxygen gas

So, 28 molecules of $NH_4$ will react with = $\frac{6}{4}\times 28=42$ molecules of oxygen gas

Hence, the molecules of oxygen gas that will be reduced to water are 42 molecules

4 0

2 years ago

Two moles of magnesium (Mg) and five moles of oxygen (O2) are placed in a reaction vessel. When magnesium is ignited, it reacts

Y_Kistochka [10]

Answer:

Explanation:

Two moles of magnesium (Mg) and five moles of oxygen (O2) are placed in a reaction vessel. When magnesium is ignited, it reacts with oxygen. What is the limiting reactant in this experiment?

Mg + O2 → MgO (unbalanced)

first, balance the equation

2Mg +O2-------> 2MgO

two magnesium atoms react with one diatomic oxygen molecule

there is a 1:1 ratio of magnesium to oxygen atoms

but we have 2 moles of magnesium atoms and 2X5 = 10 moles of oxygen atoms

the lesser magnesium LIMITS the amount of product we can make, so it is the LIMITING REAGENT.

6 0

1 year ago