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kupik [55]
3 years ago
7

How much heat is required to change 100 g of ice (H2O) at 253 K to vapor (steam) at 393 K?

Chemistry
1 answer:
soldier1979 [14.2K]3 years ago
3 0

<u>Answer:</u> The heat required will be 58.604 kJ.

<u>Explanation: </u>

To calculate the amount of heat required, we use the formula:

Q= m\times c\times \Delta T

Q= heat gained  or absorbed = ? J

m = mass of the substance = 100 g

c = heat capacity of water = 4.186 J/g ° C

Putting values in above equation, we get:

\Delta T={\text{Change in temperature}}=(393-253)K=140K=140^oC

Q=100g\times 4.186J/g^oC\times 140^oC

Q = 58604 Joules  = 58.604 kJ     (Conversion factor: 1 kJ = 1000J)

Thus, heat released by 100 grams of ice is 58.604kJ.

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Explanation:

Chemistry 1B Experiment 7

1-3 5.0 1.5 3.5

Part 2: Determining the equilibrium constant.

Label 5 medium-sized test tubes. Table 7.2 shows the amounts of 2.00 × 10–3

M

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Measure and record the absorbance of each solution at the 447 nm.

Table 7.2 Composition of solutions for determining the equilibrium constant.

Test Tube

Volume of

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Volume of

2.00 × 10–3

M KSCN

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Volume of

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2-3 5.0 3.0 2.0

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Plot a full-page graph of the absorbance against the concentration of FeSCN2+ in

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