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4 years ago

How much heat is required to change 100 g of ice (H2O) at 253 K to vapor (steam) at 393 K?

Chemistry

1 answer:

soldier1979 [14.2K]4 years ago

3 0

Answer: The heat required will be 58.604 kJ.

Explanation:

To calculate the amount of heat required, we use the formula:

$Q= m\times c\times \Delta T$

Q= heat gained or absorbed = ? J

m = mass of the substance = 100 g

c = heat capacity of water = 4.186 J/g ° C

Putting values in above equation, we get:

$\Delta T={\text{Change in temperature}}=(393-253)K=140K=140^oC$

$Q=100g\times 4.186J/g^oC\times 140^oC$

Q = 58604 Joules = 58.604 kJ (Conversion factor: 1 kJ = 1000J)

Thus, heat released by 100 grams of ice is 58.604kJ.

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Uranium-236 is _____. created by fusion reactions an unstable isotope of uranium created from four hydrogen atoms used in the H-

nata0808 [166]

Uranium-236 is intermediate nuclei. created by fusion reactions an unstable isotope of uranium created from four hydrogen atoms used in the H-bomb.

Following is the reaction involved in above process:

 $^{235}U$ + $^{1}n$ → $^{236}U$ → $^{144}Ba$ + $^{89}Kr$ + 3 $^{1}n$ + 177 MeV

Here,
$^{235}U$ = Fission material,
$^{1}n$ = projectile,
$^{236}U$ = intermediate nuclei,
$^{144}Ba$ and $^{89}Kr$ = Fission product

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3 years ago

Read 2 more answers

2Na2SO4 :How many atoms for each element are in the formula? S= O= Na=

yuradex [85]

Answer:

S= 2(1) = 2

O= 2(4) = 8

Na= 2(2) = 4

Explanation:

The given compound is:

2Na₂SO₄

An element is a distinct substance that cannot be split up into simpler substances.

So;

Number of atoms of elements here are:

S= 2(1) = 2

O= 2(4) = 8

Na= 2(2) = 4

6 0

3 years ago

How to find thr solute and solvent

olga55 [171]

the solute is the one that dissolves meaning its particles are separating into the solvent, and the solvent is the one that dissolves the other substance.

5 0

3 years ago

The thin outer layer of Earth, called the crust, contains only 0.50 percent of Earth's total mass and yet is the source of almos

Rzqust [24]

Answer:

The mass of silicon in kilograms in Earth's crust is $7.2729\times 10^{21} kg$ .

Explanation:

Mass of Earth = $5.9\times 10^{21} tons$

(1 ton= 2000 lb)

(1 lb =453.6 g)

1 ton = 2000 × 453.6 g =907,200 g

Mass of Earth = $5.9\times 10^{21}\times 907,200 g=5.3524\times 10^{27} g$

Percentage of earth crust = 0.50%

Mass of earth crust = M

$0.50\%=\frac{M}{5.3524\times 10^{27}}\times 100$

$M=2.6762\times 10^{25} g$

Percentage of the silicon in Earth's crust = 27.2 %

Mass of silicon in in Earth's crust = m

$Si\%=\frac{m}{M}\times 100$

$27.2\%=\frac{m}{2.6762\times 10^{25} g}\times 100$

$m = 7.2792\times 10^{24} g=7.2729\times 10^{21} kg$

1000 g = 1 kg

The mass of silicon in kilograms in Earth's crust is $7.2729\times 10^{21} kg$ .

7 0

3 years ago

A reaction produces 74.10 g Ca(OH)2 after 56.08 g CaO is added to 36.04 g H2O. How should the difference in the masses of reacta

melomori [17]

Cao + H2O ---->Ca(OH)2
Calculate the number of each reactant and the moles of the product
that is
moles = mass/molar mass
The moles of CaO= 56.08g/ 56.08g/mol(molar mass of Cao)= 1mole
the moles of water= 36.04 g/18 g/mol= 2.002moles
The moles of Ca (OH)2=74.10g/74.093g/mol= 1mole

The mass of differences of reactant and product can be therefore
explained as
1 mole of Cao reacted completely with 1 mole H2O to produce 1 mole of Ca(OH)2. The mass of water was in excess while that of CaO was limited

3 0

3 years ago