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1 year ago

What is responsible for the differences in chemical shift observed in carbon 4 in 4-fluoroheptane and carbon 4 in heptane?

1 answer:

4 0

The chemical shift of a given proton is decided specifically with the aid of interactions with the nearby electrons. The most necessary thing to recognize is that when electrons are subjected to an external magnetic field, they structure their own small prompted magnetic fields in opposition to the exterior field.

Consider the methane molecule ( CH4 ) in which the four equal protons have a chemical shift of 0.23 ppm (this is a price we can look up in any chemistry reference source). The valence electrons around the methyl carbon, when subjected to B0, generate their own very small triggered magnetic area that opposes B0 . This induced field, to a small however full-size degree, shields the close by protons from experiencing the full force of B0 , an impact regarded as local diamagnetic shielding. In different words, the methane protons do now not quite journey the full force of B0 - what they journey is known as Beff , or the high-quality field, which is slightly weaker than B0 due to the have an effect on of the close by electrons.

In nuclear magnetic resonance (NMR) spectroscopy, the chemical shift is the resonant frequency of an atomic nucleus relative to a preferred in a magnetic field. Often the position and range of chemical shifts are diagnostic of the shape of a molecule.

Learn more about chemical shifts here:

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Express as ordinary numbers. 3 x 100 =

Stolb23 [73]

The answer is 300
3 * 100
3 * 10 * 10
30 * 10
300

Hope this helps. If it did, consider making it Brainliest!

7 0

3 years ago

Read 2 more answers

If 1,079.75 Joules of heat are added to 77.75 grams of water, by how many degrees Celsius would the water increase? Assume water

djyliett [7]

Answer:

If 1,079.75 Joules of heat are added to 77.75 grams of water, by 3.32 degrees Celsius the temperature of water will increase

$\Delta T=3.32 C^{0}$

Explanation:

$q = mC\Delta T$

Here , q = heat added / removed from the substance

m = mass of the substance taken

$\Delta T$ = Change in temperature

C = specific heat capacity of the substance

In liquid state the value of C for water is :

$4.18 J/gC^{0}$

Given values :

q = 1079.75 J

m = 77.75 gram

Insert the value of C, m , q in the given equation

$q = mC\Delta T$

on transposing ,

$\Delta T=\frac{q}{mC}$

$\Delta T=\frac{1079.75}{77.75\times 4.18}$

$\Delta T=3.32 C^{0}$

3 0

3 years ago

Compare and contrast the uses of iron triad and the use of coinage metals

Arlecino [84]

Answer: Iron triad are used in the process to create steel and other metal mixtures. Coinage Metals are used for much more than just coins, and many other elements besides these are made into coins.

7 0

3 years ago

Read 2 more answers

Write a balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air.

Lelechka [254]

Answer: The balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is $CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$ .

Explanation:

When a substance tends to gain oxygen atom in a chemical reaction and loses hydrogen atom then it is called oxidation reaction.

For example, chemical equation for oxidation of methane is as follows.

$CH_{4} + O_{2} \rightarrow CO_{2} + H_{2}O$

Number of atoms present on reactant side are as follows.

C = 1
H = 4
O = 2

Number of atoms present on product side are as follows.

C = 1
H = 2
O = 3

To balance this equation, multiply $O_{2}$ by 2 on reactant side. Also, multiply $H_{2}O$ by 2 on product side. Hence, the equation can be rewritten as follows.

$CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$

Now, the number of atoms present on reactant side are as follows.

C = 1
H = 4
O = 4

Number of atoms present on product side are as follows.

C = 1
H = 4
O = 4

Since, the atoms present on both reactant and product side are equal. Therefore, this equation is now balanced.

Thus, we can conclude that balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is $CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$ .

4 0

3 years ago

How many molecules of co2 in 97.3 grams of co2

s2008m [1.1K]

Answer:

1.33 × 10²⁴ molecules CO₂

General Formulas and Concepts:

Chemistry - Stoichiometry

Reading a Periodic Table
Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

97.3 g CO₂

Step 2: Define conversions

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

Step 3: Convert

$97.3 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} )$ = 1.33138 × 10²⁴ molecules CO₂

Step 4: Check

We are given 3 sig figs. Follow sig fig rules.

1.33138 × 10²⁴ molecules CO₂ ≈ 1.33 × 10²⁴ molecules CO₂

8 0

3 years ago