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alina1380 [7]
2 years ago
6

What is responsible for the differences in chemical shift observed in carbon 4 in 4-fluoroheptane and carbon 4 in heptane?

Chemistry
1 answer:
Papessa [141]2 years ago
4 0

The chemical shift of a given proton is decided specifically with the aid of interactions with the nearby electrons. The most necessary thing to recognize is that when electrons are subjected to an external magnetic field, they structure their own small prompted magnetic fields in opposition to the exterior field.

Consider the methane molecule ( CH4 ) in which the four equal protons have a chemical shift of 0.23 ppm (this is a price we can look up in any chemistry reference source). The valence electrons around the methyl carbon, when subjected to B0, generate their own very small triggered magnetic area that opposes  B0 . This induced field, to a small however full-size degree, shields the close by protons from experiencing the full force of  B0 , an impact regarded as local diamagnetic shielding. In different words, the methane protons do now not quite journey the full force of  B0  - what they journey is known as  Beff , or the high-quality field, which is slightly weaker than  B0  due to the have an effect on of the close by electrons.

In nuclear magnetic resonance (NMR) spectroscopy, the chemical shift is the resonant frequency of an atomic nucleus relative to a preferred in a magnetic field. Often the position and range of chemical shifts are diagnostic of the shape of a molecule.

Learn more about chemical shifts here:

brainly.com/question/4289021

#SPJ4

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What is molarity of 47.0 g KCl dissolved in enough water to give 375 mL of solution?
natita [175]

This question provides us –

  • Weight of \bf  KCl is = 47 g
  • Volume, V = 375 mL

__________________________________________

  • Molar Mass of \bf   KCl –

\qquad \twoheadrightarrow\bf  39.0983 \times 35.453

\qquad \twoheadrightarrow\bf 74.5513

<u>Using formula</u> –

\qquad \purple{\twoheadrightarrow\bf Molarity _{(Solution)} =  \dfrac{ W\times 1000}{MV}}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \dfrac{ 47 \times 1000}{74.5513\times 375}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \dfrac{47000}{27956.7375}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = \cancel{\dfrac{47000}{27956.7375}}

\qquad \twoheadrightarrow\bf Molarity _{(Solution)}  = 1.68117M

\qquad \pink{\twoheadrightarrow\bf Molarity _{(Solution)}  = 1.7M}

  • Henceforth, Molarity of the solution is = 1.7M

___________________________________________

6 0
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