Boiling point of cyclohexane at 620 mm hg?
Standard atmospheric pressure is 760 mm Hg. Boiling point at 760 mm= 80.74˚C
A liquid boils when its vapor pressure is equal to the atmospheric pressure. The vapor pressure of a liquid is proportional the absolute temperature of the liquid.
As the atmospheric pressure decreases, less vapor pressure is needed to cause the liquid to boil. Less vapor pressure means lower temperature.
The boiling point of cyclohexane at 620 mm Hg is less than 80.74˚C
TRY THAT OR THIS
271.78
Answer:
The empirical formula is C3H3O
Explanation:
Step 1: Data given
Suppose the mass of the molecule = 100 grams
The molecule contains:
65.5 % Carbon = 65.5 grams
5.5 % Hydrogen = 5.5 grams
29.0% Oxygen = 29.0 grams
Molar mass of C = 12 g/mol
Molar mass of H = 1.01 g/mol
Molar mass of O = 16 g/mol
Step 2: Calculate moles
Moles = mass / molar mass
Moles C = 65.5 grams / 12 g/mol = 5.46 moles
Moles H = 5.5 / 1.01 g/mol = 5.45 moles
Moles O = 29.0 grams / 16 g/mol = 1.8125 moles
Step 3: Calculate mol ratio
We divide by the smallest amount of moles
C: 5.46 / 1.8125 = 3
H = 5.45 / 1.8125 = 3
O = 1.8125/1.8125 = 1
The empirical formula is C3H3O
Answer:
0.075 kg
750 dg
7.5 dag
Explanation:
1 kg = 1000 g
So, 0.075 kg = (0.075 × 1000)g = 75 g
1 dg = 0.1 g
So, 750 dg = (750 × 0.1) g = 75 g
1 dag = 10 g
So, 7.5 dag = (7.5 × 10) g = 75 g
Answer:
0.364
Explanation:
Let's do an equilibrium chart for the reaction of combustion of ammonia:
2NH₃(g) + (3/2)O₂(g) ⇄ N₂(g) + 3H₂O(g)
4.8atm 1.9atm 0 0 Initial
-2x -(3/2)x +x +3x Reacts (stoichiometry is 2:3/2:1:3)
4.8-2x 1.9-(3/2)x x 3x Equilibrium
At equilibrium the velocity of formation of the products is equal to the velocity of the formation of the reactants, thus the partial pressures remain constant.
If pN₂ = 0.63 atm, x = 0.63 atm, thus, at equilibrium
pNH₃ = 4.8 - 2*0.63 = 3.54 atm
pO₂ = 1.9 -(3/2)*0.63 = 0.955 atm
pH₂O = 3*0.63 = 1.89 atm
The pressure equilibrium constant (Kp) is calculated with the partial pressure of the gases substances:
Kp = [(pN₂)*(pH₂O)³]/[(pNH₃)²*
]
Kp = [0.63*(1.89)³]/[(3.54)²*
]
Kp = 4.2533/11.6953
Kp = 0.364
Since table salt is an ionic compound, the formula implies that numbers of Na+<span> ions, and Cl</span>-<span> ions are the same in the solid. The subscript numbers in an empirical formula should have no common divisor. A </span>structural<span> formula reflects the bonding of atoms in a molecule or ion.
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