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alina1380 [7]
2 years ago
6

What is responsible for the differences in chemical shift observed in carbon 4 in 4-fluoroheptane and carbon 4 in heptane?

Chemistry
1 answer:
Papessa [141]2 years ago
4 0

The chemical shift of a given proton is decided specifically with the aid of interactions with the nearby electrons. The most necessary thing to recognize is that when electrons are subjected to an external magnetic field, they structure their own small prompted magnetic fields in opposition to the exterior field.

Consider the methane molecule ( CH4 ) in which the four equal protons have a chemical shift of 0.23 ppm (this is a price we can look up in any chemistry reference source). The valence electrons around the methyl carbon, when subjected to B0, generate their own very small triggered magnetic area that opposes  B0 . This induced field, to a small however full-size degree, shields the close by protons from experiencing the full force of  B0 , an impact regarded as local diamagnetic shielding. In different words, the methane protons do now not quite journey the full force of  B0  - what they journey is known as  Beff , or the high-quality field, which is slightly weaker than  B0  due to the have an effect on of the close by electrons.

In nuclear magnetic resonance (NMR) spectroscopy, the chemical shift is the resonant frequency of an atomic nucleus relative to a preferred in a magnetic field. Often the position and range of chemical shifts are diagnostic of the shape of a molecule.

Learn more about chemical shifts here:

brainly.com/question/4289021

#SPJ4

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I think it’s 48.6 g/ml
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Antimony is burned in oxygen to form antimony oxide.
Zinaida [17]

The number of mole of S₂O₃ produced from the reaction is 13.33 moles

<h3>Balanced equation </h3>

4Sb + 3O₂ —> 2S₂O₃

From the balanced equation above,

3 moles of O₂ reacted to produce 2 moles of S₂O₃

<h3>How to determine the mole of S₂O₃ produced </h3>

From the balanced equation above,

3 moles of O₂ reacted to produce 2 moles of S₂O₃.

Therefore,

20 moles of O₂ will react to to produce = (20 × 2) / 3 = 13.33 moles of S₂O₃.

Thus, 13.33 moles of S₂O₃ were obtained from the reaction.

Learn more about stoichiometry:

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Answer:

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Explanation:

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3 years ago
How many atoms are in a molecule of hydrogen peroxide?
Alenkasestr [34]
2 Hydrogen and 2 Oxygen
7 0
3 years ago
Use the graph to calculate the instantaneous rate of formation of HBr at 50 s
Lina20 [59]

<u>Answer:</u> The instantaneous rate of formation of HBr at 50 s is 1.4\times 10^{-2}M/s

<u>Explanation:</u>

From the graph,

Initial rate of the Br_2 = 1.0 M

Time when the concentration of Br_2 is 0.5 M (half the concentration ) = 60 sec

For first order reaction:

Calculating rate constant for first order reaction using half life:

t_{1/2}=\frac{0.693}{k} .....(1)

t_{1/2} = half life period = 60 s

k = rate constant = ?

Putting values in equation 1:

k=\frac{0.693}{60s}\\\\k=0.01155s^{-1}

For the given chemical reaction:

H_2(g)+Br_2(g)\rightarrow 2HBr(g)

Rate of the reaction = -\frac{\Delta [Br_2]}{\Delta t}=\frac{1}{2}\frac{\Delta [HBr]}{\Delta t}

Negative sign represents the disappearance of the reactants

From the above expression:

k[Br_2]=-\frac{\Delta [Br_2]}{\Delta t}=\frac{1}{2}\frac{\Delta [HBr]}{\Delta t}

At 50 seconds, [Br_2]=0.6 M

Plugging values in above expression, we get:

\frac{1}{2}\frac{\Delta [HBr]}{\Delta t}=0.01155\times 0.6\\\\\frac{\Delta [HBr]}{\Delta t}=2\times 0.01155\times 0.6=0.01386=1.4\times 10^{-2}M/s

Hence, the instantaneous rate of formation of HBr at 50 s is 1.4\times 10^{-2}M/s

6 0
3 years ago
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