Answer:
- 273.77 rad/s^2
Explanation:
fo = 3800 rev/min = 3800 / 60 rps = 63.33 rps
f = 0
ωo = 2 π fo = 2 x 3.14 x 63.33 = 397.71 rad/s
ω = 2 π f = 0
θ = 46 revolutions = 46 x 2π radian = 288.88 radian
Let α be the angular acceleration of the centrifuge
Use third equation of motion for rotational motion
α = - 273.77 rad/s^2
Answer:
the thermal energy transferred is 183,226.68 J
Explanation:
Given;
mass of iron skillet, m = 5.1 kg
initial temperature, t₁ = 295 K
final temperature, t₂ = 373 K
The thermal energy transferred is calculated as;
Q = mcΔt
where;
Δt is change in temperature, = t₂ - t₁
c is specific heat capacity of iron = 460.6 J/kg.K
Q = 5.1 x 460.6 x (373 - 295)
Q = 183,226.68 J
Therefore, the thermal energy transferred is 183,226.68 J
Answer:
its point Y because the dot that represents Y is cose to s and can make a chan reaction
Answer:
a) 35.75 ft/s
b) 45 ft
Explanation:
<u>Given </u>
Weight W = 100 lbf
mass(m) = 100*32.174/32.2=99.92 lb
decrease in kinetic energy ΔKE = -500 ft.lbf
increase in kinetic energy ΔPE= 1500 ft.lbf
initial velocity V_1 = 40 ft/s
initial height h_1 = 30 ft/s
The gravitational acceleration g = 32.2 ft/s2 Required
(a) Final velocity V_2 (a) Final elevation h_2
<u>Solution </u>
Change in kinetic energy is defined by
ΔKE = .5*m *( V_2 ^2-V_1^2)
Change in potential energy is defined by
ΔKE = W *( h_2 -h_1 )
Then,
-500=.5*99.92*1/32.174*(V_2 ^2-40^2)
V_2=35.75 ft/s
1500 = 100 x (h_2 — 30)
h_2= 45 ft
