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Korvikt [17]
4 years ago
8

A 0.5 kg ball traveling at 1 m/s to the right hits a second ball of equal mass that is initially at rest. After the perfectly el

astic collision, the second ball travels at 0.543 m/s at a 57.2 degree angle upward from the point of contact.
Draw a before and after diagram of this collision

Physics
1 answer:
ruslelena [56]4 years ago
8 0

Comment if u dont understand

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A drag racer starts her car from rest and accelerates at 5.5 m/s2 for the entire distance of 523 m. How long did it take the car
ANEK [815]

Answer:

t = 13.7 s or t = 14 s with proper significant figures

Explanation:

The initial speed is 0 m/s since the car starts from rest, acceleration is 5.5 m/s2 and distance is 523 m.

Since we have initial speed, acceleration and distance we can use the following formula to find the time. We can now use algebra to work out our answer.

d = vt + \frac{1}{2}at²

523 = (0)t + (\frac{1}{2})(5.5)t²

523 = 2.8t²

186.8 = t²

13.7 s = t

(t = 14 s with proper significant figures)

3 0
3 years ago
The Hertzsprung-Russel diagram is used to show the relationship between which two characteristics of stars?
Dahasolnce [82]

Answer:

A

Explanation:

absolute magnitude and luminosity vs the spectral position/ temperature

5 0
3 years ago
To which layer can geologists apply the principle of faunal succession to determine the age of the layer?
BigorU [14]
A. Layer C is the right answer out of all the choices
5 0
4 years ago
A small block with mass 0.200 kg is released from rest at the top of a frictionless incline. The block travels a distance 0.796
Agata [3.3K]

Answer:

distance travelled by the block is 0.796 m

{ acceleration is independent of mass, so both the masses travel equal distance in 2 s }

Explanation:

Given that;

mass of block m = 0.200 kg

distance travelled d = 0.796 m

time t = 2.00 s

m₂ = 0.400 kg

If the 0.400 kg block is released from rest at the top of the incline, how far down the incline does it travel in 2.00 s?

Now, using the second equation of motion;

d = ut + (\frac{1}{2} × at²)

as the object started from rest, u=0

so, we substitute

0.796  = 0×2 + (\frac{1}{2} × a(2)²)

0.796  = 0 + (\frac{1}{2} × 4a)

0.796  = 2a

a = 0.796 / 2

a = 0.398 m/s²

using first equation of motion

V_{f} = u + at

we substitute

V_{f} = 0 + 0.398 × 2

V_{f} = 0.796 m/s

now, average velocity is given as;

V_{avg} = ( 0.796 m/s  + 0 ) / 2

V_{avg} = ( 0.796 m/s  + 0 ) / 2

now, distance as the block moves in 2s will be;

D = [( 0.796 m/s  + 0 ) / 2 ] × 2

D = 0.796 m

Therefore, distance travelled by the block is 0.796 m

{ acceleration is independent of mass, so both the masses travel equal distance in 2 s }

5 0
3 years ago
A tourist leaves Pittsburgh and travels 60 miles South on I-79 in 45 minutes. They exit after Wheeling and head west on I-70 and
attashe74 [19]

Answer:

<em>The tourist's average speed was 80 mph</em>

Explanation:

<u>Average Speed </u>

If an object travels a distance d in a time t regardless of the direction, the average speed is the quotient of the distance over the time:

\displaystyle v=\frac{d}{t}

The tourist leaves Pittsburgh and travels 60 miles South in 45 minutes. Then he heads West and travels 100 miles in 1 hour and 15 minutes.

The total distance traveled is:

d = 60 miles + 100 miles = 160 miles

The total time is:

t = 45 minutes + 1 hour + 15 minutes = 2 hours

The average speed is:

\displaystyle v=\frac{160}{2}

v = 80 mph

The tourist's average speed was 80 mph

8 0
3 years ago
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