Answer:
The balloon will move forward.
The density of the air will be greater at the back of the balloon; similar
to the density of air being greater at lower altitudes due to gravitational
attraction because of the weight of the air in an air column.
A block of wood in water rises because of the difference in pressures
on the top and bottom of the block.
Answer:
The correct option is;
The sports car, because it has less mass and therefore less inertia
Explanation:
Newton's first law of motion states that an object will continue in its state of rest or uniform motion in a straight line unless acted on by a force. The property exhibited by the object is known as inertia
Newton's second law states that force is directly proportional to the rate of change of momentum produced
The rate of change of momentum of an object is directly proportional to the resultant force applied and is in the direction of the resultant force. The resultant force is equal to the rate of change of momentum.
Therefore, we have;
F = m·dv/dt = m×a
Given that the force required to move an object is directly proportional to its mass therefore, the inertia or the object resistance that requires a force to bring change is directly proportional to the mass of the object.
The mass of a sports car being considered lesser than the mass of the minivan will require less force to push and therefore has less inertia.
Answer:
acceleration = 2.4525 m/s²
Explanation:
Data: Let m1 = 3.0 Kg, m2 = 5.0 Kg, g = 9.81 m/s²
Tension in the rope = T
Sol: m2 > m1
i) for downward motion of m2:
m2 a = m2 g - T
5 a = 5 × 9.81 m/s² - T
⇒ T = 49.05 m/s² - 5 a Eqn (a)
ii) for upward motion of m1
m a = T - m1 g
3 a = T - 3 × 9.8 m/s²
⇒ T = 3 a + 29.43 m/s² Eqn (b)
Equating Eqn (a) and(b)
49.05 m/s² - 5 a = T = 3 a + 29.43 m/s²
49.05 m/s² - 29.43 m/s² = 3 a + 5 a
19.62 m/s² = 8 a
⇒ a = 2.4525 m/s²
Answer:
70560 m
Explanation:
The formula to calculate the distance travelled during a free fall motion is

where
d is the distance travelled
g = -9.8 m/s^2 is the acceleration due to gravity
t is the time
In this situation,
t = 120 s
Therefore the distance travelled after 120 s is
