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earnstyle [38]
2 years ago
5

Equation for distance

Physics
1 answer:
DIA [1.3K]2 years ago
5 0

Answer:

d=√[(x₂ - x₁)² + (y₂ - y₁)²]

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The______ of a sound wave is defined as the amount of energy passing through a unit area of the wave front in a unit of time
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The intensity of a sound wave is defined as the amount of energy passing through a unit area of the wave front in unit of time.
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3 years ago
What is the mathematical relationship between wavelength and velocity? Inverse, horizontal, linear or quadratic? I NEED MAJOR HE
Tju [1.3M]

Answer: Wavelength is the measure of the length of a complete wave cycle. The velocity of a wave is the distance traveled by a point on the wave. In general, for any wave the relation between Velocity and Wavelength is proportionate. It is expressed through the wave velocity formula.

Explanation: For any given wave, the product of wavelength and frequency gives the velocity. It is mathematically given by wave velocity formula written as-

V=f×λ

Where,

V is the velocity of the wave measure using m/s.

f is the frequency of the wave measured using Hz.

λ is the wavelength of the wave measured using m. Velocity and Wavelength Relation

Amplitude, Frequency, wavelength, and velocity are the characteristic of a wave. For a constant frequency, the wavelength is directly proportional to velocity.

Given by:

V∝λ

Example:

For a constant frequency, If the wavelength is doubled. The velocity of the wave will also double.

For a constant frequency, If the wavelength is made four times. The velocity of the wave will also be increased by four times.

Hope you understood the relation between wavelength and velocity of a wave. I truely hope this helps you out tho! Goodluck!

5 0
3 years ago
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Please help (will mark brainliest)
serg [7]

Answer:

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7 0
3 years ago
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During a tennis volley, a ball that arrives at a player at 40 m/s is struck by the racquet and returned at 40 m/s. The other pla
Butoxors [25]

Answer:Racquet force is twice of Player force

Explanation:

Given

ball arrives at a speed of u=-40\ m/s

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F_{racquet}=\frac{m(v-u)}{\Delta t}

where m=mass\ of\ ball

\Delta t=time of contact of ball with racquet

F_{racquet}=\frac{m(40-(-40))}{\Delta t}

F_{racquet}=\frac{80m}{\Delta t}-----1

When it land on the player hand its final velocity becomes zero and time of contact is same as of racquet

F_{player}=\frac{m(0-40)}{\Delta t}

F_{player}=\frac{-40m}{\Delta t}-----2

From 1 and 2 we get

F_{racquet}=-2F_{player}

Hence the magnitude of Force by racquet is twice the Force by player

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3 years ago
Does the gas have a well defined structure
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What gas? Gas is an invisible form so I don't see how it would have a "defined structure".

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