It is the sum of the kinetic and potential energies of an object
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Answer:
A 5.00-g bullet is fired horizontally into a 1.20-kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.230 m along the surface before stopping.
Explanation:
Answer:
482.4 kg
Explanation:
104 calorie = 435344 J
The 2.5% of this energy equals to
435344 * 0.0025 = 10883.6 J
If this energy is converted to work done on lifting a barbell by a distance of 2.3. By the formula of Work W = force * distance then the force he exerts on the barbell is

Assuming gravitational constant g = 9.81 m/s2 then the mass of the barbell is
m = 4732 / 9.81 = 482.4 kg
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