Ask question

Ask question

All categories

3 years ago

13

A laser emits two wavelengths (λ1 = 420 nm; λ2 = 630 nm). When these two wavelengths strike a grating with 450 lines/mm, they pr

oduce maxima (in different orders) that coincide.
a. What is the order (m) of each of the two overlapping lines?
b. At what angle does this overlap occur?

1 answer:

Harlamova29_29 [7]3 years ago

8 0

Answer:

a) m = 3 for λ1 and m= 2 for λ2 will overlap since they have the same values

b) At what angle does this overlap occur = 34.54 degree

Explanation:

The detailed steps and appropriate formula is as shown in the attachment.

You might be interested in

The kinetic energy of a ball with a mass of 0.5 kg and a velocity of 10 m/s is<br> J.

Jlenok [28]

Hello!

We have the following data:

KE (Kinetic Energy) = ? (in Joule)
m (mass) = 0.5 Kg
v (speed) = 10 m/s

<span>Formula to calculate kinetic energy:

</span> $KE = \frac{1}{2} *m*v^2$
<span>
Solving:

</span> $KE = \frac{1}{2} *m*v^2$

$KE = \frac{1}{2} *0.5*10^2$

$KE = \frac{1}{2} *0.5*100$

$KE = \frac{50}{2}$

$\boxed{\boxed{KE = 25\:Joule}}\Longleftarrow(kinetic\:energy\:of\:a\:ball)\end{array}}\qquad\quad\checkmark$

I hope this helps! =)

4 0

3 years ago

Read 2 more answers

Radio waves are a type of______

Verizon [17]

Answer:

I already know the first one is electromagnetic but I don't know the second one sorry

Explanation:

5 0

3 years ago

A 80 kg skier grips a moving rope that is powered by an engine and is pulled at constant speed to the top of a 25 degrees hill.

zloy xaker [14]

Answer:

$P=28.085\,hp$

Explanation:

Given that:

mass of 1 skier, $m=80kg$

inclination of hill, $\theta=25^{\circ}$

length of inclined slope, $l=220m$

time taken to reach the top of hill, $t=2.3 min= 138 s$

coefficient of friction, $\mu=0.15$

<em>Now, force normal to the inclined plane:</em>

$F_N=m.g.cos\theta$

$F_N=80\times 9.8\times cos25^{\circ}$

$F_N=710.54\,N$

<em>Frictional force:</em>

$f=\mu.F_N$

$f=0.15\times 710.54$

$f=106.58\,N$

<em>The component of weight along the inclined plane:</em>

$W_l=m.g.sin\theta$

$W_l=80\times 9.8\times sin25^{\circ}$

$W_l=331.33\,N$

<em>Now the total force required along the inclination to move at the top of hill:</em>

$F=f+W_l$

$F=106.58+331.33$

$F=437.91\,N$

<em>Hence the work done:</em>

$W=F.l$

$W=437.91\times 220$

$W=96340.80\,J$

<em>Now power:</em>

$P=\frac{W}{t}$

$P=\frac{96340.80}{138}$

$P=698.12\,W$

<u>So, power required for 30 such bodies:</u>

$P=30\times 698.12$

$P=20943.65\,W$

$P=\frac{20943.65}{745.7}$

$P=28.085\,hp$

8 0

3 years ago

5. A little boy tries to push a heavy cupboard. He uses a force of 400 N, but he is unable to move

ad-work [718]

Answer:

NO HAY TRABAJO REALIZADO YA QUE EL NIÑO NO PUDO MOVER

EL ARMARIO, PARA QUE HAYA TRABAJO DEBE HABER DESPLAZAMIENTO.

Explanation:

8 0

3 years ago

An object has a mass of 10grams and a volume of 20m3. what is the density of the object

Pavlova-9 [17]

Explanation:

density = mass/ volume

in the question the mass is given in grams so will convert it into kg,

10 g = 0.01 kg

density= 0.01/ 20 = 1 / 2000 = 0.005 kg/m^3

7 0

3 years ago