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jeka57 [31]
3 years ago
13

A car moving in the positive direction with an initial velocity of 26 m/s slows down at a constant rate of -3 m/s2. What is its

velocity after 7 seconds of deceleration? Round the final answer to the nearest whole number.
Physics
1 answer:
Greeley [361]3 years ago
8 0
The answer is 5 m/s
- 3 =  \frac{x - 26}{ 7}  \\ x =  \frac{7 \times(  - 3)}{1}  + 26 =  - 21 + 26 \\  = 5




good luck
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If the mass of a body is 9.8kg on the earth, what would be its mass on the moon?​
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Answer:

it will remain same because mass of the body is constant everywhere

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Two service technicians are discussing the best way to thread a rod. Technician A says they should use a tap and die set. Techni
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Both technicians are right, to be able to make a threaded joint you need to use the external thread on one part of the rod using the tap and die set, and on the other side of the rod you need to have an internal thread using the thread repair insert kit

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To develop muscle tone, a woman lifts a 2.50 kg weight held in her hand. She uses her biceps muscle to flex the lower arm throug
Romashka [77]

To solve this problem we will use the concepts related to Torque as a function of the Force in proportion to the radius to which it is applied. In turn, we will use the concepts of energy expressed as Work, and which is described as the Torque's rate of change in proportion to angular displacement:

\tau = Fr

Where,

F = Force

r = Radius

Replacing we have that,

\tau = Fr

\tau = 21cm (\frac{1m}{100cm})* 550N

\tau = 11.55Nm

The moment of inertia is given by 2.5kg of the weight in hand by the distance squared to the joint of the body of 24 cm, therefore

I = 0.25Kg\cdot m^2 +(2.5kg)(0.24m)^2

I = 0.394kg\cdot m^2

Finally, angular acceleration is a result of the expression of torque by inertia, therefore

\tau = I\alpha \rightarrow \alpha = \frac{\tau}{I}

\alpha = \frac{11.55}{0.394}

\alpha = 29.3 rad/s^2

PART B)

The work done is equivalent to the torque applied by the distance traveled by 60 °° in radians (\pi / 3), therefore

W = \tau \theta

W = 11.5* \frac{\pi}{3}

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4 0
3 years ago
according to newton's second law of motion of the net force acting on the object increases while the mass of the object remains
Licemer1 [7]

Answer:

The Acceleration will increase

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It can be expressed mathematically as,

F ∝ m(v-u)/t

Where (v-u)/t = a

F  = kma.

F = force, m = mass of the body, a = acceleration, k = constant of proportionality which tend to unity for a unit force, a unit mass, and a unit acceleration.

Therefore,

F = ma.

From the equation above,

If the net force acting on a body increase, while the mass of the body remains constant, the acceleration will also increase.

4 0
3 years ago
A hot-air balloon is floating above a straight road. To estimate their height above the ground, the balloonists simultaneously m
Karolina [17]

Answer:

3.1 miles

Explanation:

To solve this question it is important to remember that the distance between two mile markers is approximately 1 mile

Once this is known, the question becomes very easy to solve. We make two triangle, which have the following three points

Triangle 1: Hot-Air-Balloon, Ground, Milepost 1 - With angle of depression 20

Triangle 2: Hot-Air-Balloon, Ground, Milepost 2 - With angle of depression 18

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From this we can simply drive two formulas using the Tan function

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Solving them simultaneously we get the value of height (h) to be 3.0852 miles or 3.1 miles

8 0
3 years ago
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