We have volume of gasoline = 14.0 gallon
Time taken to fill automobile tank = 1.50 minutes
So volume rate = 14.0 gallon/1.50 minutes = 9.33 gallon/ minute
We have density of gasoline = 0.77 kg/L = 6.073 lb/US gal
Mass rate = Density * Volume rate
= 9.33 gallon/ minute*6.073 lb/US gal = 56.68 lb/min
So mass flow rate delivered by the gasoline pump in lbm/min = 56.68
Answer:
Magnetic field, 
Explanation:
Given that,
Velocity of electron, 
It enters a region of space where perpendicular electric and a magnetic fields are present.
Magnitude of electric field, 
We need to find the magnetic field will allow the electron to go through the region without being deflected.
Magnetic force on the electron, 
.......(1)
Electric force on the electron, F = q E........(2)
From equation (1) and (2) we get:
B = 0.0002 T
or
Hence, this is the required solution.
Answer:
The answer is B).
Explanation:
The correct way to write this sentence is: After I woke up this morning, I got me a tall glass of orange juice.
Answer:
F = 200 N
Explanation:
Given that,
The mass suspended from the rope, m = 20 kg
We need to find the resultant force acting on the rope. The resultant force on the rope is equal to its weight such that,
F = mg
Where
g is acceleration due to gravity
Put all the values,
F = 20 kg × 10 m/s²
F = 200 N
So, the resultant force on the mass is 200 N.
Answer:
0.3 m
Explanation:
Initially, the package has both gravitational potential energy and kinetic energy. The spring has elastic energy. After the package is brought to rest, all the energy is stored in the spring.
Initial energy = final energy
mgh + ½ mv² + ½ kx₁² = ½ kx₂²
Given:
m = 50 kg
g = 9.8 m/s²
h = 8 sin 20º m
v = 2 m/s
k = 30000 N/m
x₁ = 0.05 m
(50)(9.8)(8 sin 20) + ½ (50)(2)² + ½ (30000)(0.05)² = ½ (30000)x₂²
x₂ ≈ 0.314 m
So the spring is compressed 0.314 m from it's natural length. However, we're asked to find the additional deformation from the original 50mm.
x₂ − x₁
0.314 m − 0.05 m
0.264 m
Rounding to 1 sig-fig, the spring is compressed an additional 0.3 meters.
