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3 years ago

10

5. Create a short poem or haiku (a poem with 5 syllables in the first line, 7 syllables in the

1 answer:

Zanzabum3 years ago

6 0

Answer:

I should write a poem,

a poem about problem,

that i'm now trying to solve,

I dont know what to involve

Explanation:

Its not haiku, cause I am not natural Englishman and I didnt want to risk any mistakes or so. It shows the problem of writing a poem about a problem. btw Im not kidding if u thought so

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Jordan's dad made a new recipe for dinner. Jordan looked at the food and saw that it was white, yellow, and purple in color. She

zhenek [66]

Answer:

Jordan used her eyes to see the food, her touch to feel the food, and her nose to smell the food, and lastly, but most importantly, she used her mouth to taste the food.

7 0

2 years ago

During the reaction, 3.50 μmol of HCl are produced. Calculate the final pH of the reaction solution. Assume that the HCl is comp

lyudmila [28]

Answer:

The pH of the solution will be equal to 5.46

Explanation:

The dissociation reaction of HCl is equal to:

HCl → H+ + Cl-

To solve the exercise we must first convert the µmoles to moles using the following conversion factor:

3.5µmoles x $\frac{1 mol}{1x10^{6} umol}$ = 3.5x $10^{-6}$ moles

Assuming a liter of solution, we can calculate the molar concentration by:

M = $\frac{Number of moles}{Liter of solution}$

Replacing:

M = $\frac{3.5x10^{-6}moles }{1 L}$ = 3.5x $10^{-6}$ moles/L

As this acid dissociates completely, the concentration of protons and chloride will be equal to 3.5x $10^{-6}$ moles/L

The pH will be equal to:

pH = -log[H+]

Replacing:

pH = -log[3.5x $10^{-6}$ ] = 5.46

8 0

4 years ago

a steel rod of 30mm diameter is enclosed centerally in a hollow copper tube of external diameter 50mm and internal 40mm. the com

masha68 [24]

Answer:

what

Explanation:

6 0

3 years ago

A cylinder 8 in. in diameter and 3 ft long is concentric with a pipe of 8.25 in internal diameter. Between the cylinder and the

yarga [219]

Answer:

What force is requiere to move the cylinder along

Explanation:

The kinematic viscosity of the ol is 0.006 fr2

5 0

3 years ago

2.5 kg of air at 150 kPa and 12°C is contained in a gas-tight, frictionless piston-cylinder device. The air is now compressed to

Korolek [52]

Answer:

Work input =283.47 KJ

Explanation:

Given that

$P_1=150\ KPa$

$P_2=600\ KPa$

T=12°C=285 K

m= 2.5 kg

Given that this is the constant temperature process.

e know that work for isothermal process

$W=P_1V_1\ln \dfrac{P_1}{P_2}$

$W=mRT\ln \dfrac{P_1}{P_2}$

So now putting the values

$W=mRT\ln \dfrac{P_1}{P_2}$

$W=2.5\times 0.287\times 285\ln \dfrac{150}{600}$

W=-283.47 KJ

Negative sign indicates that work is done on the system.

So work input =283.47 KJ

8 0

3 years ago