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dlinn [17]
3 years ago
13

When watching your weight, you want to snack smart. To do that, you want a snack that is going to __________.

Engineering
1 answer:
andreev551 [17]3 years ago
5 0
Make u be healthy ...........
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Consider a 6-bit cyclic redundancy check (CRC) generator, G = 100101, and suppose that D = 1000100100. 1. What is the value of R
dmitriy555 [2]

Answer:

The value of R is 10101

Explanation:

As per the given data

D = 1000100100

G = 100101

Redundant bit = 6-bits - 1-bit = 5-bits

No add fice zero to D

D = 100010010000000

Now calculate R as follow

R = D / G

R = 100010010000000 / 100101

R = 10101

Workings are attached with this question

3 0
3 years ago
I'm a grandma my Samuel needs to be tough in math what do I do
Sedbober [7]
Well you could always do what Hispanics do and repeat the question 2-3 times while yelling till they finally answer
7 0
3 years ago
Read 2 more answers
Suppose you wanted to convert an AC voltage to DC. Your AC voltage source has Vrms= 60V. If you use a full wave rectifier direct
vovangra [49]

Answer:

V_{dc}=84.15\ V

Explanation:

Given that

Vrms= 60 V

Vf= 0.7 V

We know that peak value of AC voltage given as

V_{o}=\sqrt{2}\ V_{rms}

Now by putting the values

V_{o}=60\sqrt{2}\ V

The output voltage of the DC current given as

V_{dc}=V_{o}-V_f

V_{dc}=60\sqrt{2}-0.7\ V

V_{dc}=84.15\ V

Therefore output voltage of the DC current is 84.15 V.

7 0
3 years ago
Technician A says that for any fuel to burn efficiently, it must be vaporized and fully mixed with the proper amount of air. Tec
Ira Lisetskai [31]

Both technicians are correct

Explanation:

They are each correct for separate reasons. Tech A is correct due to pressure and temperature both being important factors and quantities to vaporize anything. Tech B is correct due to fuel particles being easier to burn due to their chemical structure.

8 0
1 year ago
What is the thermal efficiency of a gas power cycle using thermal energy reservoirs at 627°C and 60°C? The thermal efficiency is
Vesna [10]

Answer

63 %

Explanation:

It is given that the reservoirs is at the temperature of 627°C and 27°C

So lower temperature that isT_L  = 60°C=273+60=333 K

And the higher temperature that is T_H  = 627°C =273+627=900 K

We know that the thermal efficiency of thermal reservoir = 1-\frac{T_L}{T_H}  = 1-\frac{333}{900} = 0.63 =63 %

So the efficiency of the reservoir is 63%

3 0
3 years ago
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