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frosja888 [35]
3 years ago
11

If link AB of the four-bar linkage has a constant counterclockwise angular velocity of 58 rad/s during an interval which include

s the instant represented, determine the angular acceleration of AO (positive if counterclockwise, negative if clockwise) and the acceleration of point D.
Engineering
1 answer:
katrin2010 [14]3 years ago
5 0

Answer:Vb=-6i-(-0.1ωab+8)j m/s

Explanation:

Va=V0+Va0

Va=V0+(ra0 x ωao)

ω=Angular velocity of link A0

Using r0a=0.1m;

Va=V0+(0.1i x ω0a K)

Va=0

ixk=j

Va=0+0.1ω0aj

Calculating te velocity of using te equation below

Vb=Va+Vba

Vb=Va+ωab x rba

ωab=40rad/s

rab=-0.21i+0.15j

Va=0.1ω0aj

Vb=Va+ωabxrba

Vb=0.1ω0aj+40k x -(0.21i+0.15j)

Vb=0.1ω0aj-8j-6i

Vb=-6i-(-0.1ωab+8)j m/s

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Answer:

Modulus of resilience will be 3216942.308j/m^3

Explanation:

We have given yield strength \sigma _y=818MPa

Elastic modulus E = 104 GPa

We have to find the modulus

Modulus of resilience is given by

Modulus of resilience =\frac{\sigma _y^2}{2E}, here \sigma _y is yield strength and E is elastic modulus

Modulus of resilience =\frac{(818\times 10^6)^2}{2\times 104\times 10^9}=3216942.308j/m^3  

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3 years ago
Are there engineering students here?​
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7 0
3 years ago
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Mohr's circle represents: A Orientation dependence of normal and shear stresses at a point in mechanical members B The stress di
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Answer:

The correct answer is A : Orientation dependence of normal and shear stresses at a point in mechanical members

Explanation:

Since we know that in a general element of any loaded object the normal and shearing stresses vary in the whole body which can be mathematically represented as

\sigma _{x'x'}=\frac{\sigma _{xx}+\sigma _{yy}}{2}+\frac{\sigma _{xx}-\sigma _{yy}}{2}cos(2\theta )+\tau _{xy}sin(2\theta )

And \tau _{x'x'}=-\frac{\sigma _{xx}-\sigma _{yy}}{2}sin(2\theta )+\tau _{xy}cos(2\theta )

Mohr's circle is the graphical representation of the variation represented by the above 2 formulae in the general oriented element of a body that is under stresses.

The Mohr circle is graphically displayed in the attached figure.

4 0
2 years ago
a coil consists of 200 turns of copper wire and has a cross-sectional area of 0.8mm square . The mean length per turn is 80 cm a
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Answer:

The picture below with the answer. Hope it helps, have a great day/night and stay safe! Length of the coil,

8 0
3 years ago
A steady stream (1000 kg/hr) of air flows through a compressor, entering at (300 K, 0.1 MPa) and leaving at (425 K, 1 MPa). The
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Answer:

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The explanation to these solution is on the first, second , third and fourth uploaded image respectively

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