Answer:
10.19 m/s
Explanation:
See the attached picture.
Answer:
Foliated rocks Metamorphic grade
A .Schist Second-highest grade
B.Slate lowest grade
C.Gneiss Highest grade
D. Phyllite Second- lowest grade
Explanation:
Metamorphic grade of rocks generate when existing rock transform new to new rock and this is known as met aphorism.
Foliated rocks Metamorphic grade
A .Schist Second-highest grade
B.Slate lowest grade
C.Gneiss Highest grade
D. Phyllite Second- lowest grade
Answer:
A. -0.003
B. 0.02
Explanation:
<u>Step 1:</u> identify the given parameters
Giving the following parameters
Wing area (S)= 1.5 m²
Wing chord (C) = 0.45 m
Velocity (V) = 100 m/s
moment about center of gravity(Mcg) = -12.4 N-m
at another angle of attack, L = 3675 N and Mcg = 20.67 N-m
<u>Step 2:</u> calculate the value of the moment coefficient about the aerodynamic center (Cmcg)
![q_{∞} =\frac{1}{2}\rho*v^{2}](https://tex.z-dn.net/?f=q_%7B%E2%88%9E%7D%20%3D%5Cfrac%7B1%7D%7B2%7D%5Crho%2Av%5E%7B2%7D)
= 6125 N/m²
![C_{mcg,w} =\frac{M_{cg,w} }{q_{∞}*S*C }](https://tex.z-dn.net/?f=C_%7Bmcg%2Cw%7D%20%3D%5Cfrac%7BM_%7Bcg%2Cw%7D%20%7D%7Bq_%7B%E2%88%9E%7D%2AS%2AC%20%7D)
= -0.003
at zero lift
<u>Step 3</u>: calculate coefficient of lift
Cl = L/q*s
Cl = 3675/6125*1.5 = 0.4
<u>Step 4:</u> calculate the location of the aerodynamic center
New moment coefficient about the aerodynamic center (Cmcg):
= 0.005
![C_{mcg,w} = C_{ac} ,w + C_{l}(h-h_{ac})](https://tex.z-dn.net/?f=C_%7Bmcg%2Cw%7D%20%3D%20C_%7Bac%7D%20%2Cw%20%2B%20C_%7Bl%7D%28h-h_%7Bac%7D%29)
![h-h_{ac}= \frac{C_{mcg,w} -C_{ac,w}}{C_{l} }](https://tex.z-dn.net/?f=h-h_%7Bac%7D%3D%20%5Cfrac%7BC_%7Bmcg%2Cw%7D%20-C_%7Bac%2Cw%7D%7D%7BC_%7Bl%7D%20%7D)
=0.02
the location of the aerodynamic center = 0.02
Solution :
Given :
The power of the air‐conditioning (AC) unit is , W = 0.434 kW
The coefficient of performance or the COP of the air‐conditioning (AC) unit is given by = 6.22
Therefore he heat removed is given by , ![$Q_H = 6.22 \times 0.434$](https://tex.z-dn.net/?f=%24Q_H%20%3D%206.22%20%5Ctimes%200.434%24)
![$Q_H = 2.7 \ kW $](https://tex.z-dn.net/?f=%24Q_H%20%3D%202.7%20%5C%20kW%20%24)
Now if the electricity is valued at 0.10 dollar per kW hour, then the operating cost of the air conditioning unit in 24 hours is given by = 0.10 x 2.7 x 24
= 6.48
Therefore the operating cost = $ 6.48 for 24 hours.
Answer:
#include <iostream>
#include <iomanip>
using namespace std;
class pointType
{
public:
pointType()
{
x=0;
y=0;
}
pointType::pointType(double x,double y)
{
this->x = x;
this->y = y;
}
void pointType::setPoint(double x,double y)
{
this->x=x;
this->y=y;
}
void pointType::print()
{
cout<<"("<<x<<","<<y<<")\n";
}
double pointType::getX()
{return x;
}
double pointType::getY()
{return y;
}
private:
double x,y;
};
int main()
{
pointType p2;
double x,y;
cout<<"Enter an x Coordinate for point ";
cin>>x;
cout<<"Enter an y Coordinate for point ";
cin>>y;
p2.setPoint(x,y);
p2.print();
system("pause");
return 0;
}