Answer:
AUG, ribosome, initiation, translation
Explanation:
The transfer of information from DNA to RNA to protein is called Central Dogma. The formation of protein from mRNA is translation. The translation begins with initiator codon AUG in mRNA. The ribosome small subunit (30s) binds to the RNA. The tRNA binds and then large subunit (50s) attaches with mRNA.
Thus, reading from 5’ to 3’, this RNA product has the sequence <u>AUG.</u> It binds to the small subunit of the <u>ribosome.</u> It is joined by the large subunit, completing the <u>initiation</u> stage of the process of <u>translation</u>.
Answer:
B. Decrease to its carrying capacity
Explanation:
Goby fish feed over algae for their survival and growth but if 50% of algae in the ocean decreases then the population of goby fish will decrease to its carrying capacity.
This is so because then the goby fish will be dependent on the left number of algae and maximum population size will depend on the rest 50% of food or algae available.
Hence, the correct answer is "B. Decrease to its carrying capacity".
Answer:
Women who carry one copy of the mutated gene still have normal color vision because they have another copy, which is not mutated, in the other X chromosome that will be the dominant one. As a result, the women are carriers of the mutated gene but not color blind.
Explanation:
Colorblindness is a sex-linked mutation. A woman has two X chromosomes, while a man has one X chromosome and one Y chromosome. The mutated gene that causes color blindness is on the X chromosome, and it is OPN1LW. So if a woman has one mutated OPN1LW in one of her two X chromosomes, the OPN1LW gene in the other X chromosome will be the dominant one stopping the woman from being colorblind.
In the case of men, as they only have one X chromosome, if there is a mutation on the OPN1LW in the X chromosome, the men will be colorblind because there is no extra copy of the gene, as it is in women.
The concave disc shape of red blood cells Maximizes the surface area of the cell , allowing for rapid movement of oxygen or carbon dioxide to and form the hemoglobin within the cell.
Answer:
similarity
Starch, cellulose,dextran and glycogen are all polymers of glucose
differences
monomer/glucose glycosidic bond branching
1.starch α glucose 1-4 and 1-6 branch and unbranced
amylose 1-4 unbranched
amylopectin 1-4 and 1-6 branched
2. dextran α glucose 1-6 branched
3. cellulose β glucose 1-4 unbranched, linear
4. glycogen α glucose 1-4 and 1-6 branched (shorter
branches than starch)
Enzyme: amlase acts on starch and cellulase acts on cellulose as they are specific for their substrates.
Explanation:
Starch: Consists of both branched amylopectin and unbranched amylose
Enzymes: Enzymes are specific as the gulcose molecule in starch is α and in cellulose is β which differ in their position of hydroxyl groups at anomeric carbon, their structures differ so they form different bonds. Active sites of enzymes can act only on specific bonds a sthey can fit to their specific substrates.
