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KatRina [158]
3 years ago
12

z jaka maksymalna predkoscia porusza sie przez krotka chwile rowerzysta jezeli dysponuje moca maksymalna 420w i przy predkosci z

ktora sie porusza musi pokonac sile oporu 35N?
Physics
1 answer:
qwelly [4]3 years ago
6 0

Answer:

12 m/s

Explanation:

English Translation

At what maximum speed is the cyclist traveling for a short time if he has a maximum power of 420W and at this speed he must overcome the resistance 35N.

The Power, P, expended by a moving body with velocity, v, moving against a resistive force of F is given as

P = Fv

P = 420 W

F = 35 N

v = ?

420 = 35v

v = (420/35) = 12 m/s

In Polish/Po polsku

Moc P, wydana przez poruszające się ciało z prędkością v, poruszająca się przeciw sile oporu F, jest podana jako

P = Fv

P = 420 W

F = 35 N

v = ?

420 = 35v

v = (420/35) = 12 m/s

Hope this Helps!!!

Mam nadzieję że to pomoże!!!

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what is the wavelength of radio waves transmitted by an FM station at 90MHz where 1M=10^6, and speed of radiowave is 3*10^8m/s
Igoryamba

Answer:

λ = 3.33 m

Explanation:

<u><em>Given:</em></u>

Frequency = f = 9 × 10⁷ Hz

Speed = v = 3 × 10⁸ m/s

<u><em>Required:</em></u>

Wavelength = λ = ?

<u><em>Formula:</em></u>

v = fλ

<u><em>Solution:</em></u>

<em>Putting the givens in the formula</em>

v = fλ

λ = \frac{v}{f}

λ = \frac{3*10^8}{9*10^7}

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5 0
3 years ago
Two 1 MHz radio antennas emitting in-phase are separated by600
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Answer:

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Explanation:

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