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erma4kov [3.2K]
2 years ago
14

Dry ice (solid CO2) has occasionally been used as an "explosive" in mining. A hole is drilled, dry ice and a small amount of gun

powder are placed in the hole, a fuse is added, and the hole is plugged. When lit, the exploding gunpowder rapidly vaporizes the dry ice, building up an immense pressure. Assume that 391 g of dry ice is placed in a cavity with a volume of 0.770 L and the ignited gunpowder heats the CO2 to 695 ∘C. What is the final pressure inside the hole?
Chemistry
1 answer:
Zielflug [23.3K]2 years ago
3 0

Answer:

Final pressure = 0.77atm

Explanation:

The concept used to approach this question is the Ideal gas equation

PV = nRT

where P = pressure

V = Volume

n = number of mole or amount of substance

R = ideal gas constant

T = Temperature in Kelvin

  • from the parameters given ; mass = 391g
  • volume = 0.770 L
  • Temperature = 695 ∘C = 695 + 273 = 968K
  • R = 0.0821
  • number of moles = mass/molar mass
  • molar mass of CO2 = 12 + 2x16 = 44g/mol
  • number of moles = 391g/44g/mol = 8.886mol

plugging into the equation to get the final pressure,

  • from PV = nRT
  • P = nRT/V = 8.886 x 0.0821 x 968 / 0.770
  • Final pressure = 0.77atm
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