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Temka [501]
3 years ago
15

An average reaction rate is calculated as the change in the concentration of reactants or products over a period of time in the

course of the reaction. And instantaneous reaction rate is the rate at a particular moment in the reaction and is usually determined graphically. The reaction of compound A forming compound B was studied and the following data were collected:
Col1 Time 0. 200. 500. 800. 1200. 1500.
Col2 [A] (M) 0.184 0.129 0.069 0.031 0.019 0.016
What is the average reaction rate between 0. and 1500. s?rate = ??? (3 sig figs)What is the average reaction rate between 200. and 1200.s ?
rate = ??? (3 sig figs)What is the instantaneous rate of the reaction at t=800. s?rate = ?? (2 sig figs)
Chemistry
1 answer:
Aliun [14]3 years ago
4 0

Answer:

The average reaction rate between 0 and 1500 s?rate =1.12*10^{-4} M/s.  The average reaction rate between 200 and 1200 s ?  rate =1.10*10^{-4} M/s. The instantaneous rate of the reaction at t=800 s?rate =7.1*10^{-5} M/s.

Explanation:

The average rate of a chemical reaction is a function of the change in the concentration of reactants  or products and the time taken for the change to happen.  The instantaneous rate is estimated by considering the average rate at the smallest possible time interval such as Δt tends to zero.

1) The average reaction rate between 0 and 1500 s?

rate = (0.184-0.016)M/(1500-0)s =1.12*10^{-4} M/s.

2) The average reaction rate between 200 and 1200 s ?

rate = (0.129-0.019)M/(1200-200)s =1.10*10^{-4} M/s.

3) The instantaneous rate of the reaction at t=800 s?

In this case, we consider the data directly before and after the given point. Such as (0.069 M, 500 s) and (0.019 M,1200 s)

instantaneous rate = (0.069 - 0.019)M/(1200-500)s =7.1*10^{-5} M/s.

We ignore the negative sign because we are only interested in the magnitude of the reaction rate.

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. Sulfur dioxide can be produced in the laboratory by the reaction of hydrochloric acid and a sulfite salt such as sodium sulfit
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Answer:

Mass of SO₂ can be made from 25.0 g of Na₂SO₃ and 22 g of HCl = 12.672 g

Explanation:

SO₂( sulfur dioxide) can be produced in the lab. by the reaction of hydrochloric acid & sulphite salt such as sodium.

        the balanced chemical equation is as follows

                       Na₂SO₃ + 2 HCl → 2 NaCl + SO₂ + H₂O

Moles of Na₂SO₃ = \frac{Mass}{Molecular mass} =\frac{25}{126} = 0.198

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      For sodium sulfite \frac{mole}{stoichiometry}  = \frac{0.198}{1}= 0.198

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since <u>sodium sulfite</u> is <u>limiting reactant</u> for above chemical reaction

1 mole of Na₂SO₃ produce 1 mole of SO₂

0.198 mole of Na₂SO₃ produce 0.198 mole of SO₂

∴ Mass of SO₂ produce = mole x molar mass of SO₂

                                       = 0.198 x 64

                                       = 12.672 g

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