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Shtirlitz [24]
2 years ago
6

5.01 *10^-7-30*10^-9

Mathematics
1 answer:
777dan777 [17]2 years ago
4 0

Answer:

\large\boxed{4.71\times10^{-7}}

Step-by-step explanation:

5.01\times10^{-7}-30\times10^{-9}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=5.01\times10^{-9+2}-30\times10^{-9}\\\\=5.01\times10^{-9}\cdot10^2-30\times10^{-9}\\\\=(5.01\cdot10^2)\times10^{-9}-30\times10^{-9}\\\\=(5.01\cdot100)\times10^{-9}-30\times10^{-9}\\\\=501\times10^{-9}-30\times10^{-9}\qquad\text{distribute}\\\\=(501-30)\times10^{-9}\\\\=471\times10^{-9}\\\\=4.71\cdot10^2\times10^{-9}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=4.71\times10^{2+(-9)}\\\\=4.71\times10^{-7}

or

5.01\times10^{-7}-30\times10^{-9}\\\\=5.01\times10^{-7}-30\times10^{-7+(-2)}\\\\=5.01\times10^{-7}-30\times10^{-7}\cdot10^{-2}\\\\=5.01\times10^{-7}-(30\cdot10^{-2})\times10^{-7}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=5.01\times10^{-7}-\left(30\cdot\dfrac{1}{10^2}\right)\times10^{-7}\\\\=5.01\times10^{-7}-\left(30\cdot\dfrac{1}{100}\right)\times10^{-7}\\\\=5.01\times10^{-7}-(30\cdot0.01)\times10^{-7}\\\\=5.01\times10^{-7}-0.3\times10^{-7}\qquad\text{distribute}\\\\=(5.01-0.3)\times10^{-7}\\\\=4.71\times10^{-7}

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Answer:

  see the attachment

Step-by-step explanation:

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Based on our assumption, we want to create a simulation that includes a 1/5 chance of the day being a Friday, along with a 2/3 chance that the class has a lab experiment on whatever day it is.

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The simulation of 70 different choices of a random class is shown in the attachment.

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<em>Comment on the question</em>

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