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natka813 [3]
3 years ago
9

Which of the following statements are true? I. The number of protons in an element is the same for all neutral atoms of that ele

ment. II. The number of electrons in an element is the same for all neutral atoms of that element. III. The number of neutrons in an element is the same for all neutral atoms of that element. Select one:
Physics
1 answer:
FromTheMoon [43]3 years ago
6 0

Answer:

Both statements I, and II are true

Explanation:

I)One is true.The number of protons of the element is the defining characteristic of it. This is, if we take a proton or add a proton to a nucleus we will be changing the element. Therefore, the number of protons is the same for all neutral and not neutral atoms of that element.

II)Two is true. If an atom is neutral, it will have the same number of electrons and protons. As the number of protons for an element cannot change (see I), then the number of electrons will be the same for all neutral atoms of this element.

III)Three is false. We can have a neutral atoms of the same element with different number of neutrons, as neutrons do not change the charge of the atom(they change their mass, though). These are called Isotopes.

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Heat transfer in liquids or gases that happens due to currents of hot and cold is called
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Convection

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If your prediction turns out to be false your experiment has been a failure
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A typical wall outlet voltage is 120 volts in the United States. Personal MP3 players require much smaller voltages, typically 2
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Answer:        

Number of turns in secondary will be 7

Explanation:

We have given primary voltage V_p=120volt

Number of turns in the primary is N_p=3575

Secondary voltage is given V_s=235mV=0.235volt

We have to find the number of turns in secondary

We know that \frac{N_p}{N_s}=\frac{V_p}{V_s}

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6 0
3 years ago
4. Una cuerda de acero de piano mide 1.60 m de longitud y 0.20 cm de diámetro. ¿Cuál es la tensión en la cuerda si se estira 0.2
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Answer:

1030.83\ \text{N}

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\Delta L = Cambio en la longitud de la cuerda = 0.25 cm

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d = Diámetro de la cuerda = 0.2 cm

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El cambio de longitud de una cuerda viene dado por

\Delta L=\dfrac{TL}{AE}\\\Rightarrow T=\dfrac{\Delta LAE}{L}\\\Rightarrow T=\dfrac{0.25\times 10^{-2}\times \dfrac{\pi}{4}(0.2\times 10^{-2})^2\times 210\times 10^9}{1.6}\\\Rightarrow T=1030.84\ \text{N}

La tensión en la cuerda es 1030.84\ \text{N}.

8 0
2 years ago
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