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natka813 [3]
3 years ago
9

Which of the following statements are true? I. The number of protons in an element is the same for all neutral atoms of that ele

ment. II. The number of electrons in an element is the same for all neutral atoms of that element. III. The number of neutrons in an element is the same for all neutral atoms of that element. Select one:
Physics
1 answer:
FromTheMoon [43]3 years ago
6 0

Answer:

Both statements I, and II are true

Explanation:

I)One is true.The number of protons of the element is the defining characteristic of it. This is, if we take a proton or add a proton to a nucleus we will be changing the element. Therefore, the number of protons is the same for all neutral and not neutral atoms of that element.

II)Two is true. If an atom is neutral, it will have the same number of electrons and protons. As the number of protons for an element cannot change (see I), then the number of electrons will be the same for all neutral atoms of this element.

III)Three is false. We can have a neutral atoms of the same element with different number of neutrons, as neutrons do not change the charge of the atom(they change their mass, though). These are called Isotopes.

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Why do atoms form bonds by donating, accepting or sharing electrons with other atoms?
sineoko [7]

Answer:

atoms form bonds by donating, accepting or sharing electrons with other atoms in order to complete their valence shell electrons

hence , C. Bonding gives an atom the same number of protons as a noble gas.

Explanation:

i hope it helped

7 0
3 years ago
how much force is needed to move a brick with a mass of 345-kg a distance of 28m while doing 1008 j of work?
Travka [436]

    Work = (force) x (distance)

     1,008 J  =  (force) x (28 m)

Divide each side by 28m  :    (1,008 kg-m²/sec²) / (28 m)  =  force

                                           Force =  36 kg-m/s²  =  36 Newtons .
                                                                      (about 8.1 pounds)

It doesn't matter what that force accomplishes.
It could be moving a brick, lifting a fish, or pushing a little red wagon.
In order to do 1,008 joules of work in 28 meters, it takes 36 N of force,
in the direction of the 28 meters.
5 0
3 years ago
WILL NAME BEST ANSWER THE BRAINLIEST (if you answer well)
mylen [45]
The best and most correct answer among the choices provided by the question is third choice. What happened during the set-up was the e<span>xcess protons move from the positive rod to the negative rod.</span> I hope my answer has come to your help. God bless and have a nice day ahead!
7 0
4 years ago
PLEASE ANSWER, 75 PTS, AND BRANLIEST!
n200080 [17]

Answer:

An electromagnet is a device which moving electric charges(current) in a coil of wire create a magnet. Electromagnets can easily be turned off and on because it is a electromagnet. When current flows through a wire, a magnetic field is produced around a wire and create an electromagnet. The coils are always made of copper wire because copper is a good conductor of electricity.

Explanation:

7 0
3 years ago
A raindrop of mass 0.5 * 10^-4 kg is falling verctically under the influence of gravity. The air drag on the raindrop is fdrag =
Elina [12.6K]

Answer:

The displacement of the air drop after 3 second is 18.27 m.

Explanation:

Mass of the rain drop = m = 0.5\times 10^{-4} kg

Weight of the rain drop = W

Duration of time = t = 3 seconds

W=m\times g

Drag force on rain drop = D=0.2\times 10^{-5} v^2

W=0.5\times 10^{-4} kg\time 10 m/s^2=0.5\times 10^{-3} N

Motion of the rain drop:

F=m\times a

Net force on the rain drop , F=  W - D

W-D=m\times a

0.5\times 10^{-3} N-0.2\times 10^{-5} v^2=0.5\times 10^{-4} kg\times a

0.5\times 10^{-3} kg m/s^2-0.2\times 10^{-5} v^2=0.5\times 10^{-4} kg\times \frac{v}{t}

0.006v^2+0.05v-1.5=0

v = 12.18 m/s

Initial velocity of the rain drop = u = 0 (since, it is starting from rest)

v=u+at (First equation of motion)

12.18 m/s=0m/s+a\times 3 s

a=4.06 m/s^2

s=ut+\frac{1}{2}at^2 (second equation of motion)

s=0\times 3s+\frac{1}{2}\times 4.06m/s^2\times (3 s)^2

s = 18.27 m

The displacement of the air drop after 3 second is 18.27 m.

6 0
3 years ago
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