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2 years ago

According to Bohr each orbit an electron could travel in had a certain amount of ________ associated with it.

Physics

1 answer:

Lena [83]2 years ago

6 0

The awnser to your problem would be a as in energy

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नारायणको तौल 70kg छ । उसले 3m उचाइ भएको रूख चढ्न 20 sec मा लाग्छ भने

Serga [27]

Sorry I tbh don’t understand wat ur saying

7 0

2 years ago

How many photons per second are emitted by the antenna of a microwave oven if its power output is 1.00 kw at a frequency of 2515

Norma-Jean [14]

The power of the antenna is
$P=1.00 kW=1000 W$
and since the power is the emitted energy divided by the time, the energy emitted per second is
$E=Pt = (1000 W)(1 s)=1000 J$

The frequency of the emitted photons is
$f=2515 MHz=2.515 \cdot 10^9 Hz$
So the energy of a single photon is
$E_1=hf=(6.6 \cdot 10^{-34} Js)(2.515 \cdot 10^9 Hz)=1.66 \cdot 10^{-24} J$

Therefore, to find the number of emitted photons per second, we should divide the total energy emitted by the antenna in 1 second by the energy of a single photon:
$N= \frac{E}{E_1}= \frac{1000 J}{1.66 \cdot 10^{-24} J}= 6.02 \cdot 10^{26}$

8 0

2 years ago

Si: A + B = C – D es una ecuación física donde A, B, C y D son magnitudes físicas entonces [ A ] = [ B ] = [ C ] = [ D ]

PilotLPTM [1.2K]

Answer:

$[A] = [B] = [C] = [D]$ por el Principio de Homogeneidad Dimensional y el uso de operaciones de adición y sustracción.

Explanation:

Por el Principio de Homogeneidad Dimensional, A, B, C y D deben tener las mismas magnitudes físicas para la realización de operaciones de adición y sustracción. Es decir:

$[A] + [B] = [C] - [D]$ , donde $[A] = [B] = [C] = [D]$

8 0

2 years ago

Why are airplanes filled with pressurized air and oxygen

zimovet [89]

Answer:

Airplane cabins are pressurized because as the airplane climbs higher in altitude, the air becomes very thin, this pressurization ensures that there is still enough breathable oxygen in the cabin to prevent everyone from suffering the effects of hypoxia and passing out.

plz give brainlist :'D

7 0

2 years ago

At some instant and location, the electric field associated with an electromagnetic wave in vacuum has the strength 71.9 V/m. Fi

kirza4 [7]

Answer:

a) Magnetic field strength, B = 2.397 * 10⁻⁷ T

b) Total energy density, U = 4.58 * 10⁻⁸ J/m³

c) Power flow per unit area, S = 13.71 W/m²

Explanation:

a) Electric field strength, E = 71.9 V/m

The relationship between the Electric field strength and the magnetic field strength in vacuum is:

E = Bc where c = 3.0 * 10⁸ m/s

71.9 = B * 3.0 * 10⁸

B = 71.9 / (3.0 * 10⁸)

B = 23.97 * 10⁻⁸

B = 2.397 * 10⁻⁷ T

b) Total Energy Density:

$U = \frac{1}{2} \epsilon_0E^2 + \frac{1}{2} \frac{B^2}{\mu_0} \\U = \frac{1}{2}* 8.85 * 10^{-12}*71.9^2 + \frac{1}{2} \frac{(2.397*10^{-7})^2}{4\pi*10^{-7}}\\U = 2.29 * 10^{-8} + 2.29 * 10^{-8}\\U = 4.58 * 10^{-8} J/m^3$

c)Power flow per unit area

$S = \frac{1}{\mu_0} EB\\S = \frac{1}{4\pi * 10^{-7} } * 71.9 * 2.397 * 10^{-7}\\S = 13.71 W/m^2$

6 0

2 years ago