It can be transmit in hydraulic machine, exerting a small cross-sectional area can lead to pressure being transmitted
The work function is what we call the minimum energy that is required by an electron to leave the metal target in the photoelectric effect.
We have: Energy(E) = Planck's constant(h) × Frequency(∨)
Here, Planck's constant(h) = 6.626 × 10⁻³⁴ J/s
Frequency (∨) = 3.16 × 10¹² /s
Substitute the values into the expression:
E = (6.626 × 10⁻³⁴)(3.16 × 10¹²) J
E = 2.093 × 10⁻²¹ Joules
In short, Your Final answer would be 2.093 × 10⁻²¹ J
Hope this helps!
Answer:
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Explanation:
