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Talja [164]
2 years ago
13

Studies have shown that viewing violent actions in the media __________ the inhibition against performing those actions, especia

lly if the behavior is rewarded or results in positive benefits. A. increases B. decreases C. does not affect D. intensifies
Physics
2 answers:
Alex777 [14]2 years ago
8 0

Answer:

B. Decreases

Explanation:

According to differential reinforcement theory, one of the social learning theories, when behaviors are rewarded with the certain positive actions or positive outcomes then it is called positive enforcement. Positive enforcement increases the criminal actions. On the other hand, negative enforcement increases the actions which reduce the criminal activities.  

According to theory explained above Studies have shown that viewing violent actions in the media decreases the inhibition against performing those actions when behavior is rewarded with the positive enforcement.

Airida [17]2 years ago
4 0

Answer:

Decreases

Explanation:

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For work to be done on an object,
djverab [1.8K]

Answer:B

Explanation:

For work to be done, the object must move some distance as a result of a force

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3 years ago
If a train is 100 kilometers away, how much sooner would you hear the train coming by listening to the rails (iron) as opposed t
Whitepunk [10]
From tables, the speed of sound at 0°C is approximately
V₁ = 331 m/s (in air)
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Time required to travel in air is
t₁ = d/V₁ = 10⁵/331 = 302.12 s

Time required to travel in iron is
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Answer:  283 s (nearest second)



6 0
2 years ago
What do radio waves and gamma rays have in common?
Reil [10]

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7 0
3 years ago
Read 2 more answers
A 62.0-kg athlete leaps straight up into the air from a trampoline with an initial speed of 9.6 m/s. The goal of this problem is
pochemuha

Answer:

2856.96 J

0

0

\frac{1}{2}mv_i^2+mgh_i=\frac{1}{2}mv_f^2+mgh_f

6.78822 m/s

Explanation:

v_i = Initial velocity = 9.6 m/s

g = Acceleration due to gravity = 9.81 m/s²

h = Height

The athlete only interacts with the gravitational potential energy. Air resistance is neglected.

At height y = 0

Kinetic energy

K=\frac{1}{2}mv^2\\\Rightarrow K=\frac{1}{2}\times 62\times 9.6^2\\\Rightarrow K=2856.96\ J

At height y = 0 the potential energy is 0 as

P=mgy\\\Rightarrow P=mg0=0

At maximum height her velocity becomes 0 so the kinetic energy becomes zero.

As the the potential and kinetic energy are conserved

The general equation

K_i+P_i=K_f+P_f\\\Rightarrow \frac{1}{2}mv_i^2+mgh_i=\frac{1}{2}mv_f^2+mgh_f

Half of maximum height

\\\Rightarrow mgh_i+\frac{1}{2}mv_f^2=mg\frac{h_i}{2}+\frac{1}{2}mv^2\\\Rightarrow gh_i=g\frac{h_i}{2}+\frac{1}{2}v^2\\\Rightarrow g\frac{h_i}{2}=\frac{1}{2}v^2\\\Rightarrow v=\sqrt{gh}

h_i=\frac{v_i^2}{2g}

v=\sqrt{gh}\\\Rightarrow v=\sqrt{g\times \frac{v_i^2}{2g}}\\\Rightarrow v=\sqrt{\frac{v_i^2}{2}}\\\Rightarrow v=\sqrt{\frac{9.6^2}{2}}\\\Rightarrow v=6.78822\ m/s

The velocity of the athlete at half the maximum height is 6.78822 m/s

8 0
2 years ago
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