Jose has $2.50 in nickels and dimes in his jar. If he has 11 more nickels than dimes, how many dimes does he have?
1 answer:
Jose has $2.50 cents in total,
We need an equation to solve this. We will let d=dime.
dime=.10
nickel=.05
.10d + .05 (d + 11)=2.50
.10d + .05d + 0.55= 2.50
.15d + 0.55 = 2.50
.15d= 1.95
d= 13
There is 13 dimes. To get the nickels, you just add the 11 to 13 and you get 24 nickels.
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