What is 10 to 8 out of 32

What value of x is in the solution set of 9(2x + 1) < 9x - 18? <br> -4<br> -3<br> -2<br> -1

Anastaziya [24]

Answer:

The only possible answer that is correct is the first one, x = -4.

Step-by-step explanation:

Simplify the given inequality as much as possible, and then substitute each of the given x values one by one to determine which is in the solution set.

9(2x + 1) < 9x - 18 becomes 18x + 9 < 9x - 18, which, if reduced by dividing all four terms by 9, becomes 2x + 1 < x - 2.

Simplifying further, we get x < - 3. The only possible answer that is correct is the first one, x = -4. -4 < -3 is true.

8 0

3 years ago

Read 2 more answers

The weekly ad for a local grocery store advertises a 5 pound bag of organic apples for $13.95. Round each rate to the nearest hu

stich3 [128]

Answer:

Step-by-step explanation:

Given that in the weekly ad 5 pound bag of organic apples will cost 13.95 dollars

To find unit rate

Unit rate can be found in two ways either cost of 1 apple or no of apples for 1 dollars

I part:

5 apples = 13.95 dollars

1 apple = 13.95/5 (since direct variation)

Unit rate for one apple= 2.79 dollars

Part II:

13.95 dollars = 1 apple

1 dollar = 1/13.95 = 0.071

=0.07

But normally since apples are countable as 1,2 ... we use the first type of rate only unit rate per apple

6 0

4 years ago

Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. (a) Descr

Daniel [21]

Answer:

(a) The sampling distribution of $\overline{X}$ = Population mean = 79

(b) P ( $\overline{X}$ greater than 81.2 ) = 0.1357

(c) P ( $\overline{X}$ less than or equals 74.4 ) = .0107

(d) P (77.6 less than $\overline{X}$ less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean $(\nu)$ = 79

Standard deviation $(\sigma )$ = 18

(a) Describe the sampling distribution of $\overline{X}$

For large sample using central limit theorem

the sampling distribution of $\overline{X}$ = Population mean = 79

(b) What is Upper P ( $\overline{X}$ greater than 81.2 ) =

$P(\overline{X}> 81.2)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})$

= $P(Z> 1.1)$

= $1 - P(Z< 1.1)$

= 1 - .8643 =

= 0.1357

(c) What is Upper P ( $\overline{X}$ less than or equals 74.4 ) =

$P(\overline{X}\leq 74.4)$ = $P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{74.4- 79}{\frac{18}{\sqrt{81}}})$

= $P(Z\leq -2.3)$

= .0107

(d) What is Upper P (77.6 less than $\overline{X}$ less than 83.2 ) =

$P(77.6< \overline{X}< 83.2)$ = $P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq \frac{83.2- 79}{\frac{18}{\sqrt{81}}})$