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MaRussiya [10]
3 years ago
14

What is 10 to 8 out of 32

Mathematics
2 answers:
Sergio [31]3 years ago
6 0

Answer: I think it’s 0.25

Step-by-step explanation:

frez [133]3 years ago
3 0
it gotta be 25% ...
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What is the expanded notation of (-4)^3
lubasha [3.4K]

Answer:

A

Step-by-step explanation:

(- 4)³ means - 4 multiplied by itself 3 times, that is

(- 4)³ = - 4 × - 4 × - 4 → A

6 0
3 years ago
A cannonball is shot straight up into the air. The height of the cannonball at time t is represented by the function f(t)=−16t^2
san4es73 [151]

Answer:

the initial height

Step-by-step explanation:

given the height is represented by the function

f(t) = - 16t² + 40t + 3

Then the initial height is when t = 0, that is

f(0) = 0 + 0 + 3 = 3 ← initial height

7 0
3 years ago
3. Raphael bought 14 pounds of meat to make hamburgers at the Fourth of
Svetradugi [14.3K]
Raphael needs 9 packages of buns
first you need to multiply 14 by 5 to get 70 which is how many hamburgers will be made. then divide 70 by 8 to see how many packages will be needed. you get 8.75 by doing this so you have to round up to 9 to have enough.
4 0
3 years ago
Turn 0.059 into a fraction then find the percent
CaHeK987 [17]

Answer:

59/1000

Step 1: Write down the decimal divided by 1, like this: decimal 1 Step 2: Multiply both top and bottom by 10 for every number after the decimal point. (For example, if there are two numbers after the decimal point, then use 100, if there are three then use 1000, etc.)

7 0
3 years ago
An economist wants to estimate the mean income for the first year of work for college graduates who have had the profound wisdom
suter [353]

Answer:

We need at least 601 incomes.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How many such incomes must be found if we want to be 95% confident that the sample mean is within $500 of the true population mean?

We have to find n, for which M = 500, \sigma = 6250. So

M = z*\frac{\sigma}{\sqrt{n}}

500 = 1.96*\frac{6250}{\sqrt{n}}

500\sqrt{n} = 1.96*6250

\sqrt{n} = \frac{1.96*6250}{500}

(\sqrt{n})^{2} = (\frac{1.96*6250}{500})^{2}

n = 600.25

Rounding up

We need at least 601 incomes.

3 0
4 years ago
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