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AfilCa [17]
3 years ago
6

Classify the solutions of 3/x+5+1/5=2x+5 as extraneous or non-extraneous

Mathematics
1 answer:
dedylja [7]3 years ago
7 0
It's <span>extraneous. I know this because it leads to a straight answer. 
</span>
<span><span><span><span>3x</span>+5</span>+<span>15</span></span>=<span><span>2x</span>+5</span></span><span><span><span><span>
26x</span>+15</span><span>5x</span></span>=<span><span>2x</span>+5</span></span>
<span><span><span>26x</span>+15</span>=<span><span>10<span>x2</span></span>+<span>25x</span></span></span><span><span><span><span>
26x</span>+15</span>−<span>(<span><span>10<span>x2</span></span>+<span>25x</span></span>)</span></span>=<span><span><span>10<span>x2</span></span>+<span>25x</span></span>−<span>(<span><span>10<span>x2</span></span>+<span>25x</span></span>)
</span></span></span>
−10x2+x+15=0<span>
x=<span><span><span>−b</span>±<span>√<span><span>b2</span>−<span><span>4a</span>c</span></span></span></span><span>2a</span></span></span><span>
x=<span><span><span>−<span>(1)</span></span>±<span>√<span><span><span>(1)</span>2</span>−<span><span>4<span>(<span>−10</span>)</span></span><span>(15)</span></span></span></span></span><span>2<span>(<span>−10</span>)</span></span></span></span><span>
x=<span><span><span>−1</span>±<span>√601</span></span><span>−20</span></span></span><span><span>
x=<span><span>120</span>+<span><span><span><span><span>−1</span>20</span><span>√601</span></span><span> or </span></span>x</span></span></span>=<span><span>120</span>+<span><span>120</span><span>√601</span></span></span></span><span>
x=<span><span>120</span>+<span><span><span>−1</span>20</span><span>√601
</span></span></span></span><span>
x=<span><span>120</span>+<span><span>120</span><span>√601</span></span></span></span>
<span><span>x=<span><span>120</span>+<span><span><span><span><span>−1</span>20</span><span>√601</span></span><span> or </span></span>x</span></span></span>=<span><span>120</span>+<span><span>120</span><span>√<span>601

Hoped I helped!</span></span></span></span></span>
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Anuta_ua [19.1K]

Answer:

we conclude that the relationship between distance and time is NOT proportional.

Hence, she did not drive at a constant speed.

Step-by-step explanation:

We know that when 'y' varies directly with 'x', we get the equation

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y = kx

k = y/x

where 'k' is called the constant of proportionality.

In our case, the table shows the distance Allison drove on one day of her vacation.

Time (h)              1         2        3          4        5

Distance (mi)       55    100     165     280    250

using the equation

k = y/x

susbtitute y = 55, x = 1

k = 55/1 = 55

substitute y = 100, x = 2

k = y/x

k = 100 / 2 = 50

substitute y = 165, x = 3

k = y/x

k = 165 / 3 = 55

substitute y = 280, x = 4

k = y/x

k = 280 / 4 = 70

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k = y/x

k = 250 / 5 = 50

It is clear that the value of 'k' does not remain constant.

Therefore, we conclude that the relationship between distance and time is NOT proportional.

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Savatey [412]
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