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3 years ago

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Classify the solutions of 3/x+5+1/5=2x+5 as extraneous or non-extraneous

1 answer:

dedylja [7]3 years ago

7 0

It's <span>extraneous. I know this because it leads to a straight answer.
</span>
<span><span><span><span>3x</span>+5</span>+<span>15</span></span>=<span><span>2x</span>+5</span></span><span><span><span><span>
26x</span>+15</span><span>5x</span></span>=<span><span>2x</span>+5</span></span>
<span><span><span>26x</span>+15</span>=<span><span>10<span>x2</span></span>+<span>25x</span></span></span><span><span><span><span>
26x</span>+15</span>−<span>(<span><span>10<span>x2</span></span>+<span>25x</span></span>)</span></span>=<span><span><span>10<span>x2</span></span>+<span>25x</span></span>−<span>(<span><span>10<span>x2</span></span>+<span>25x</span></span>)
</span></span></span>
−10x2+x+15=0<span>
x=<span><span><span>−b</span>±<span>√<span><span>b2</span>−<span><span>4a</span>c</span></span></span></span><span>2a</span></span></span><span>
x=<span><span><span>−<span>(1)</span></span>±<span>√<span><span><span>(1)</span>2</span>−<span><span>4<span>(<span>−10</span>)</span></span><span>(15)</span></span></span></span></span><span>2<span>(<span>−10</span>)</span></span></span></span><span>
x=<span><span><span>−1</span>±<span>√601</span></span><span>−20</span></span></span><span><span>
x=<span><span>120</span>+<span><span><span><span><span>−1</span>20</span><span>√601</span></span><span> or </span></span>x</span></span></span>=<span><span>120</span>+<span><span>120</span><span>√601</span></span></span></span><span>
x=<span><span>120</span>+<span><span><span>−1</span>20</span><span>√601
</span></span></span></span><span>
x=<span><span>120</span>+<span><span>120</span><span>√601</span></span></span></span>
<span><span>x=<span><span>120</span>+<span><span><span><span><span>−1</span>20</span><span>√601</span></span><span> or </span></span>x</span></span></span>=<span><span>120</span>+<span><span>120</span><span>√<span>601

Hoped I helped!</span></span></span></span></span>

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