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3 years ago

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Solve equation 3x 6= -1

1 answer:

VLD [36.1K]3 years ago

7 0

if the equation is 3x + 6 = -1, then 3x = -7 so x = 2.333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333333

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CAN SOMEONE HELP ME FAST

a_sh-v [17]

Answer is <span>A. y=14x

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8 0

3 years ago

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How many significant figures does 0.0102 have?

kakasveta [241]

1. Non-zero digits are significant
2. Zeroes between two significant numbers are significant
3. Trailing zeroes are significant

0.0102 has 3 <span>significant figures
1 and 2 are non-zero digits (Rule 1)
0 between 1 and 2 is zero between </span>two significant numbers (Rule 2)

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3 years ago

First-order linear differential equations

kkurt [141]

Answer:

$(1)\ logy\ =\ -sint\ +\ c$

$(2)\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Step-by-step explanation:

1. Given differential equation is

$\dfrac{dy}{dt}+ycost = 0$

$=>\ \dfrac{dy}{dt}\ =\ -ycost$

$=>\ \dfrac{dy}{y}\ =\ -cost dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}$

$=>\ logy\ =\ -sint\ +\ c$

Hence, the solution of given differential equation can be given by

$logy\ =\ -sint\ +\ c.$

2. Given differential equation,

$\dfrac{dy}{dt}\ -\ 2ty\ =\ t$

$=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty$

$=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})$

$=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}$

$=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c$

$=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Hence, the solution of given differential equation is

$log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

8 0

4 years ago

Suppose that the cost of a rental car is $65 for a week plus 0.15 per mile driven.

IceJOKER [234]

You have the following equation for the cost of renting a car for x number of miles driven:

y = 0.15x + 65

If you travel 70 miles, then, x = 70 and you obtain for the cost y:

y = 0.15(70) + 65

y = 10.5 + 65

y = 75.5

Hence, the cost of renting a car to drive 70 miles is $75.5

3 0

1 year ago

The annual income of Sam is Rs 43,360. What is his monthly income if he earns an equal amount every month?

tankabanditka [31]

His monthly income if he earns an equal amount every month is Rs 3,613.33

<h3>How to determine the monthly income?</h3>

The annual income is given as:

Annual income = Rs 43,360

The monthly income is calculated as

Monthly income = Annual income/Number of months

There are 12 months in a year

So, we have:

Monthly income = Rs 43,360/12

Evaluate the quotient

Monthly income = Rs 3,613.33

Hence, his monthly income if he earns an equal amount every month is Rs 3,613.33

Read more about average at:

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2 years ago