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Cerrena [4.2K]
3 years ago
10

How many 4/5's are in 1

Mathematics
1 answer:
jolli1 [7]3 years ago
8 0

Answer: 5/4

Step-by-step explanation:

To get the number of groups of 4/5 are in 1, we divide 1 by 4/5. This will give:

= 1 ÷ 4/5

= 1 × 5/4

= 5/4

<h3>There are 5/4 groups of 4/5 in 1.</h3>
You might be interested in
4x/x+3 - 4x/x+6 <br> Please help me find the right answer thxs
Arisa [49]

Answer:

9

Step-by-step explanation:

For 4x/x+3, just cancel the x to get 4+3=7

For -4x/x+6, cancel the x to get -4+6=2

7+2=9

Hope this helps

6 0
3 years ago
Tropical forests are being lost at the rate of 5 million hectares per year. how many hectares per day is that? how many hectares
katrin [286]
5,000,000/365= 13,698.630137 hectatres per day /1440 = 9.5129375951388..... hectares per minute

365 days in a year
1440 minutes in a day (24hrs)


7 0
3 years ago
John’s gross pay for the week is $500. He pays 1.45 percent in Medicare tax, 6.2 percent in Social Security tax, 2 percent in st
olchik [2.2K]
Gross pay = 500

deductions :
medicare tax : 0.0145(500) = 7.25
S.S tax : 0.062(500) = 31.00
sales tax : 0.02(500) = 10.00
income tax : 0.2(500) = 100
insurance = 20
total deductions : 7.25 + 31 + 10 + 100 + 20 = 168.25

gross pay - deductions = net pay
500 - 168.25 = net pay
331.75 = net pay <===
7 0
3 years ago
The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or
tigry1 [53]

<u>Answer-</u>

<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>

<u>Solution-</u>

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}


P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67

Putting these values,

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%

5 0
3 years ago
Can someone simplify8x + 5x please
igor_vitrenko [27]

Answer:

13x

because you would comibne like terms, so you add the 8 and 5.

6 0
2 years ago
Read 2 more answers
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